【发布时间】:2013-08-22 10:53:58
【问题描述】:
所以我的应用设置带有共享操作按钮,该按钮将当前 URL 共享到 Twitter 或 Facebook,但是当我单击 Facebook 按钮时,它会显示一个 Twiiter 共享表。 (Tiwtter 选项工作正常)
点击 FACEBOOK 选项后,在 iPhone 上进行测试时,会出现标准的推特分享表。
- (IBAction)social:(id)sender {
UIActionSheet *share = [[UIActionSheet alloc] initWithTitle:@"Pass on the news!" delegate:self cancelButtonTitle:@"OK" destructiveButtonTitle:nil otherButtonTitles:@"Post to Twitter", @"Post to Facebook", nil];
//You must show the action sheet for the user to see it.
[share showInView:self.view];
}
- (void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex {
//Each button title we gave to our action sheet is given a tag starting with 0.
if (actionSheet.tag == 0) {
//Check Twitter accessibility and at least one account is setup.
if([SLComposeViewController isAvailableForServiceType:SLServiceTypeTwitter]) {
SLComposeViewController *tweetSheet =[SLComposeViewController composeViewControllerForServiceType:SLServiceTypeTwitter];
[tweetSheet addURL:self.newsItemWebView.request.URL]; //This is setting the initial text for our share card.
[tweetSheet setInitialText:@"Check out this article I found using the 'Pass' iPhone app:, "];
//Brings up the little share card with the test we have pre defind.
[self presentViewController:tweetSheet animated:YES completion:nil];
} else {
//This alreat tells the user that they can't use built in socal interegration and why they can't.
UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Sorry" message:@"You can't send a tweet right now, make sure you have at least one Twitter account setup and your device is using iOS6 or above!." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alertView show];
}
} else if (actionSheet.tag == 1) {
//Check Facebook accessibility and at least one account is setup.
if([SLComposeViewController isAvailableForServiceType:SLServiceTypeFacebook]) {
SLComposeViewController *facebookSheet =[SLComposeViewController composeViewControllerForServiceType:SLServiceTypeFacebook];
[facebookSheet addURL:self.newsItemWebView.request.URL];
//This is setting the initial text for our share card.
[facebookSheet setInitialText:@"Check out this article I found using the 'Pass' iPhone app:"];
//Brings up the little share card with the test we have pre defind.
[self presentViewController:facebookSheet animated:YES completion:nil];
} else {
//This alreat tells the user that they can't use built in socal interegration and why they can't.
UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Sorry" message:@"You can't post a Facebook post right now, make sure you have at least one Facebook account setup and your device is using iOS6 or above!." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alertView show];
}
}
}
【问题讨论】:
-
为什么不使用
UIActivityViewController? -
@rckoenes 是的,我对此很陌生,但这听起来像是一种更好的方法!我仍然可以使用 addURL:self.newsItemWebView.request.URL 行将当前 URL 添加到共享表吗?非常感谢朋友!
-
不,你需要传递一些你想分享的对象。只需将 URL 添加到数组并将其传递给
[[UIActivityViewController alloc] initWithActivityItems:items applicationActivities:nil];,其中items是包含您的 URL 的数组。 -
@rckoens 非常感谢,我会在我回到电脑前试一试,然后标记为已回答! (:出于兴趣,你知道为什么它不能使用我的方法吗?它仍然困扰着我。
-
您在 if 语句中使用的是
actionSheet.tag而不是buttonIndex。
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