【发布时间】:2015-07-05 16:54:30
【问题描述】:
我在共享按钮中有代码:
NSString *aText = _textToOutput;
UIImage *aPhoto = [[UIImage alloc] initWithData: _photoData];
NSURL *website = [NSURL URLWithString:@"http://www.google.com/"];
NSArray *objectsToShare = @[aText, aPhoto, website];
/* NSArray *includeActivities = @[UIActivityTypeMessage,
UIActivityTypeMail,
UIActivityTypePostToFacebook,
UIActivityTypePostToTwitter,
UIActivityTypePostToFlickr]; */
UIActivityViewController *activityVC = [[UIActivityViewController alloc] initWithActivityItems:objectsToShare applicationActivities:nil];
NSArray *excludeActivities = @[UIActivityTypeAirDrop,
UIActivityTypeCopyToPasteboard,
UIActivityTypePrint,
UIActivityTypeAssignToContact,
UIActivityTypeSaveToCameraRoll,
UIActivityTypeAddToReadingList,
UIActivityTypePostToFlickr,
UIActivityTypePostToVimeo];
activityVC.excludedActivityTypes = excludeActivities;
[self presentViewController:activityVC animated:YES completion:nil];
}
但我可以向我们发送短信和电子邮件,并且所有 3 个要共享的对象都会出现。但是在 twitter 上,URL 没有出现在弹出窗口中,而在 Facebook 上,弹出窗口中缺少 URL 和 NSString。 ios 或这些应用程序有什么变化吗?谢谢。
【问题讨论】:
-
我认为这可能是问题所在。 openradar.appspot.com/18940777
标签: ios facebook twitter ios8 uiactivityviewcontroller