scrapy-splash 脚本有问题。我只得到一个结果，我的刮刀不解析其他页面

Question

我正在尝试解析来自 javascript 网站的列表。当我运行它时，它只在每一列上返回一个条目，然后蜘蛛关闭。我已经设置了我的中间件设置。我不确定出了什么问题。提前致谢！

import scrapy
from scrapy_splash import SplashRequest


class MalrusSpider(scrapy.Spider):
    name = 'malrus'
    allowed_domains = ['backgroundscreeninginrussia.com']
    start_urls = ['http://www.backgroundscreeninginrussia.com/publications/new-citizens-of-malta-since-january-2015-till-december-2017/']

    def start_requests(self):
        for url in self.start_urls:
            yield SplashRequest(url=url,
                                callback=self.parse,
                                endpoint='render.html')

    def parse(self, response):
        russians = response.xpath('//table[@id="tablepress-8"]')
        for russian in russians:
            yield{'name' : russian.xpath('//*[@class="column-1"]/text()').extract_first(),
                  'source' : russian.xpath('//*[@class="column-2"]/text()').extract_first()}

        script = """function main(splash)
                assert(splash:go(splash.args.url))
                splash:wait(0.3)
                button = splash:select("a[class=paginate_button next] a")
                splash:set_viewport_full()
                splash:wait(0.1)
                button:mouse_click()
                splash:wait(1)
                return {url = splash:url(),
                        html = splash:html()}
            end"""

        yield SplashRequest(url=response.url,
                            callback=self.parse,
                            endpoint='execute',
                            args={'lua_source': script})

Answer 1

您使用的 .extract_first()（现在是 .get()）将始终返回第一个结果。它不是一个迭代器，所以多次调用它是没有意义的。您应该尝试 .getall() 方法。这将是这样的：

names = response.xpath('//table[@id="tablepress-8"]').xpath('//*[@class="column-1"]/text()').getall()
sources = response.xpath('//table[@id="tablepress-8"]').xpath('//*[@class="column-2"]/text()').getall()