CORONA SDK：如何停止事件循环？

Question

在开发我的应用程序时，我遇到了两个问题，因为我不明白如何通过事件停止循环。 我编写了以下代码来复制这个问题。

在我的 App 中有一个复杂的模型，需要最多两分钟的时间来计算解决方案。

我希望能够显示计算过程中经过的时间，并通过单击两个不同的按钮来停止或重新开始计算（为简单起见，代码中有两个圆圈）。

从下面的代码中可以看出，我可以查看经过的时间，只有在同一个循环完成时才停止循环。

有人遇到过这个问题吗？

对不起英语。 感谢您提供的提示

问候， 詹卢卡

local calculation_progress=true

local messagge_obj=display.newText("Start Calculation",display.contentCenterX-200, display.contentCenterY-200, native.systemFont, 40)
messagge_obj:setTextColor( 255, 255, 255 )

--- here there is a simple function, but in my App is a complex loop that works until 2 minutes
local function loop_fun()
    messagge_obj.text="Calculation started"
    local max_comps=1000000
    for i=1,max_comps do
        if calculation_progress==true then
            local messagge_loop=tostring(i) --- here is a simple model  
            print(messagge_loop)
        else
            break
        end
    end
    messagge_obj.text="Calculation done"
end

--- setting of the timer
local test_time_label = display.newText("Time:", display.contentCenterX-125, display.contentCenterY-50, native.systemFont, 40 )
local test_time = display.newText("", display.contentCenterX-20, display.contentCenterY-10, native.systemFont, 40 )
local function refresh_time()
    local currentTime = os.date("*t")
    test_time.text=os.time( t ) --currentTime
end
Runtime:addEventListener("enterFrame",  refresh_time)

--- setting of play and stop button
local function play_calc()
    calculation_progress=true
    loop_fun()
    print("calculation_progress",calculation_progress)
end
local function stop_calc()
    calculation_progress=false
    print("calculation_progress",calculation_progress)
end
local myButton_calc_play = display.newCircle(display.contentCenterX+60,display.contentCenterY+200,60)
local test_play = display.newText("Play", display.contentCenterX+10,display.contentCenterY+180, native.systemFont, 45 )
test_play:setTextColor(0)
test_play:addEventListener("tap",  play_calc)
local myButton_calc_stop = display.newCircle(display.contentCenterX-100,display.contentCenterY+200,60)
local test_stop = display.newText("Stop", display.contentCenterX-145,display.contentCenterY+180, native.systemFont, 45 )
test_stop:setTextColor(0)
test_stop:addEventListener("tap",  stop_calc)

--- loop inside model
loop_fun()

Answer 1

我不完全了解您的需求。以下是您需要的吗？

local statusLabel
local calculation_progress = false
local timer_1

local messageLabel =display.newText("Start Calculation",90,90, native.systemFont, 20)
messageLabel:setTextColor( 255, 255, 255 )

local minVal = 02
local secVal = 00

local minLabel = display.newText("0"..minVal,130,120, native.systemFont, 20)
local secLabel = display.newText(":0"..secVal,160,120, native.systemFont, 20)

local function timerDown()
    secVal = secVal - 1
    if(secVal<0 and minVal<=0)then
        if(timer_1)then timer.cancel(timer_1) end
        statusLabel.text = "Play"
        print("Timer stopped... Calculation Finished...")
        return true;
    end
    if(secVal<=0 and minVal>0)then
        secVal = 59
        minVal = minVal - 1
    end
    secLabel.text = ":"..secVal
    minLabel.text = minVal
    if(secVal<10)then secLabel.text = ":0"..secVal end
    if(minVal<10)then minLabel.text = "0"..minVal end
    print(secVal)
end

local function myCalculationChanger()
    --[[I've assigned this to a single button,
        if you want, you can separate them --]]
    if(calculation_progress==false)then  -- First click to start
        calculation_progress = true
        statusLabel.text = "Stop"
        timer_1 = timer.performWithDelay(1000,timerDown,-1)
    else                                 -- Next click to restart
        if(timer_1)then timer.cancel(timer_1) end
        minVal = 02
        secVal = 00
        secLabel.text = ":"..secVal
        minLabel.text = minVal
        if(secVal<10)then secLabel.text = ":0"..secVal end
        if(minVal<10)then minLabel.text = "0"..minVal end

        statusLabel.text = "Play"
        calculation_progress = false
    end
end

local myButton = display.newCircle(0,0,60)
myButton.x = display.contentWidth/2
myButton.y = display.contentHeight-100
myButton:addEventListener("tap",myCalculationChanger)

statusLabel = display.newText("Play",20,20,nil,40)
statusLabel.x = myButton.x
statusLabel.y = myButton.y
statusLabel:setTextColor(0)

继续编码...... :)

Answer 2

非常感谢您的回复和您发布的代码。 但我的意图是退出计算循环很长时间（直到 2-5 分钟）。 我已经通过 COPROA SDK 论坛中收到的建议解决了这个问题 代码下方。

问候， 詹卢卡

local calculation_progress=true local messagge_obj=display.newText("Start Calculation",display.contentCenterX-200, display.contentCenterY-200, native.systemFont, 40) messagge_obj:setTextColor( 255, 255, 255 ) --- function to exit from loop function verify_progress_loop() local outcome=true if calculation_progress==false then outcome=false end return outcome end --- here there is a simple function, but in my App is a complex loop that works until 2 minutes local max_comps=100000 local n_min_cicle=100 local n_delay=max_comps/n_min_cicle local function loop_fun() local t local i=0 local function doWork() for j=1,n_min_cicle do local outcome=verify_progress_loop() if outcome==true then local messagge_loop=tostring(i) --- here is a simple model print(messagge_loop) else messagge_obj.text="Calculation stopped" timer.cancel(t) --return 0 end i=i+1 if i==max_comps then messagge_obj.text="Calculation done" timer.cancel(t) end end end t=timer.performWithDelay( 0.1, doWork, n_delay ) end --- setting of the timer local test_time_label = display.newText("Time:", display.contentCenterX-125, display.contentCenterY-50, native.systemFont, 40 ) local test_time = display.newText("", display.contentCenterX-20, display.contentCenterY-10, native.systemFont, 40 ) local function refresh_time() local currentTime = os.date("*t") test_time.text=os.time( t ) --currentTime end Runtime:addEventListener("enterFrame", refresh_time) --- setting of play and stop button local function play_calc(event) messagge_obj.text="Calculation started" calculation_progress=true loop_fun() print("Inside play_cal function") return true end local function stop_calc(event) calculation_progress=false print("Inside stop_cal function") return true end local myButton_calc_play = display.newCircle(display.contentCenterX+60,display.contentCenterY+200,60) local test_play = display.newText("Play", display.contentCenterX+10,display.contentCenterY+180, native.systemFont, 45 ) test_play:setTextColor(0) test_play:addEventListener("tap", play_calc) local myButton_calc_stop = display.newCircle(display.contentCenterX-100,display.contentCenterY+200,60) local test_stop = display.newText("Stop", display.contentCenterX-145,display.contentCenterY+180, native.systemFont, 45 ) test_stop:setTextColor(0) test_stop:addEventListener("tap", stop_calc)

Answer 3

使用此代码。

本地 t

本地计数 = 1

本地函数 loop_fun()

如果计算进度==true 并且计数

      messagge_obj.text="Calculation started"
      local messagge_loop=tostring(count) --- here is a simple model  
        print(messagge_loop)
        count = count + 1
        t = timer.performWithDelay( 0.1, loop_fun)

其他

      messagge_obj.text="Calculation done"
      timer.cancel(t)

结束

结束

并在计算进度标志之后调用 stop_calc() 内的 loop_fun()。