【发布时间】:2011-03-09 11:13:07
【问题描述】:
虽然我们在 Substitution 控件中使用的方法应该返回字符串,但是如何在应该呈现在服务器端的服务器控件上的 Web 表单中使用 donut caching?
比如Loginview控件?
【问题讨论】:
标签: asp.net caching substitution webforms donut-caching
虽然我们在 Substitution 控件中使用的方法应该返回字符串,但是如何在应该呈现在服务器端的服务器控件上的 Web 表单中使用 donut caching?
比如Loginview控件?
【问题讨论】:
标签: asp.net caching substitution webforms donut-caching
更新 现在这是一个完整的工作示例。这里发生了一些事情:
这是标记:
<asp:Substitution runat="server" methodname="GetCustomersByCountry" />
这是回调
public string GetCustomersByCountry(string country)
{
CustomerCollection customers = DataContext.GetCustomersByCountry(country);
if (customers.Count > 0)
//RenderView returns the rendered HTML in the context of the callback
return ViewManager.RenderView("customers.ascx", customers);
else
return ViewManager.RenderView("nocustomersfound.ascx");
}
这里是渲染用户控件的辅助类
public class ViewManager
{
private class PageForRenderingUserControl : Page
{
public override void VerifyRenderingInServerForm(Control control)
{ /* Do nothing */ }
public override bool EnableEventValidation
{
get { return false; }
set { /* Do nothing */}
}
}
public static string RenderView(string path, object data)
{
PageForRenderingUserControl pageHolder = new PageForUserControlRendering();
UserControl viewControl = (UserControl) pageHolder.LoadControl(path);
if (data != null)
{
Type viewControlType = viewControl.GetType();
FieldInfo field = viewControlType.GetField("Data");
if (field != null)
{
field.SetValue(viewControl, data);
}
else
{
throw new Exception("ViewFile: " + path + "has no data property");
}
}
pageHolder.Controls.Add(viewControl);
StringWriter result = new StringWriter();
HttpContext.Current.Server.Execute(pageHolder, result, false);
return result.ToString();
}
}
查看这些相关问题:
【讨论】:
Micah 的答案遗漏了一点,替换函数必须是static,接受HttpContext 参数,并返回string。请参阅this msdn page 了解更多信息。
我还扩展了Micah 的助手类,使其更加灵活。
标记
<asp:Substitution ID="Substitution1" MethodName="myFunction" runat="server" />
实施
public static string myFunction(HttpContext httpContext){
ViewManager vm = new ViewManager();
//example using a Button control
Button b = new Button();
b.Text = "click me"; //we can set properties like this
//we can also set properties with a Dictionary Collection
Dictionary<string,object> data = new Dictionary<string,object>();
data.add("Visible",true);
String s = vm.RenderView(b,data); //don't do anything (just for example)
//we can also use this class for UserControls
UserControl myControl = vm.GetUserControl("~mypath");
data.clear();
data.add("myProp","some value");
return vm.RenderView(myControl,data); //return for Substitution control
}
类
using System.IO;
using System.ComponentModel;
public class ViewManager
{
private PageForRenderingUserControl pageHolder;
public ViewManager()
{
pageHolder = new PageForRenderingUserControl();
}
public UserControl GetUserControl(string path)
{
return (UserControl)pageHolder.LoadControl(path);
}
public string RenderView(Control viewControl, Dictionary<string, object> data)
{
pageHolder.Controls.Clear();
//Dim viewControl As UserControl = DirectCast(pageHolder.LoadControl(Path), UserControl)
if (data != null) {
Type viewControlType = viewControl.GetType();
dynamic properties = TypeDescriptor.GetProperties(viewControl);
foreach (string x in data.Keys) {
if ((properties.Item(x) != null)) {
properties.Item(x).SetValue(viewControl, data[x]);
}
}
}
pageHolder.Controls.Add(viewControl);
StringWriter result = new StringWriter();
HttpContext.Current.Server.Execute(pageHolder, result, false);
return result.ToString();
}
private class PageForRenderingUserControl : Page
{
public override void VerifyRenderingInServerForm(Control control)
{
// Do nothing
}
public override bool EnableEventValidation {
get { return false; }
// Do nothing
set { }
}
}
}
再次感谢Micah 提供代码
【讨论】:
我相当确定您不能这样做 - 替换控件将仅允许您将字符串插入到输出缓存页面中。
如果您考虑服务器控件的整个输出,这是有道理的,这可能是<table>,它会破坏您精心制作的所有标记和/或需要将<script> 加载到页面中的东西 - 而注入单个字符串是相对简单的。
【讨论】: