【发布时间】:2021-06-06 14:22:48
【问题描述】:
我有一个类 MemberInfo。有一个属性是照片。现在我想创建一个具有属性值的 memberinfo 对象。代码如下:
let info = new MemberInfo();
info.MemberId = "101";
info.MemberName = "Mohammad Nasir Uddin";
info.Type = "General";
info.Category = "A";
info.BloodGroup = "B+";
info.MobileNo = "012589652357";
info.Photo = this.sanitizer.bypassSecurityTrustUrl("'https://www.gravatar.com/avatar/205e460b479e2e5b48aec07710c08d50'");
info.ShopNo = "101";
info.ShopName = "Yellow Computers";
info.Floor = "First Floor";
this.selectedMember = info;
为了制作安全的图片网址,我已经对其进行了清理。但它显示了编译时错误:
类型“SafeUrl”不可分配给类型“字符串”。信息.照片 = this.sanitizer.bypassSecurityTrustUrl("'https://www.gravatar.com/avatar/205e460b479e2e5b48aec07710c08d50'")
要将照片绑定到 html,我使用了以下代码:
<img [src]="selectedMember.Photo" class="mr-2">
我该如何解决这个问题?
【问题讨论】:
标签: angular sanitization