如何遍历python的svg元素[重复]

Question

我一直在尝试遍历页面上具有定义特征的所有 svg 元素，然后单击它们并进行解析，但只发现了如何打开第一个元素 你知道怎么全部打开吗？ 任何反馈表示赞赏:)

<tr class="MuiTableRow-root">
  <td class="MuiTableCell-root jss346 MuiTableCell-alignLeft MuiTableCell-sizeSmall MuiTableCell-body">АМАРИЛ М ТАБЛ. П/ПЛЕН/ОБ. 2МГ+500МГ №30</td>
  <td class="MuiTableCell-root jss346 MuiTableCell-alignRight MuiTableCell-sizeSmall MuiTableCell-body">1</td>
  <td class="MuiTableCell-root jss346 MuiTableCell-alignLeft MuiTableCell-sizeSmall MuiTableCell-body"><a class="MuiTypography-root MuiLink-root MuiLink-underlineHover jss348 MuiTypography-colorPrimary"><svg class="MuiSvgIcon-root jss350" focusable="false" viewBox="0 0 24 24" aria-hidden="true" role="presentation"><path d="M18 17H6v-2h12v2zm0-4H6v-2h12v2zm0-4H6V7h12v2zM3 22l1.5-1.5L6 22l1.5-1.5L9 22l1.5-1.5L12 22l1.5-1.5L15 22l1.5-1.5L18 22l1.5-1.5L21 22V2l-1.5 1.5L18 2l-1.5 1.5L15 2l-1.5 1.5L12 2l-1.5 1.5L9 2 7.5 3.5 6 2 4.5 3.5 3 2v20z"></path></svg></a></td>
</tr>
<tr class="MuiTableRow-root">
  <td class="MuiTableCell-root jss346 MuiTableCell-alignLeft MuiTableCell-sizeSmall MuiTableCell-body">АМАРИЛ М ТАБЛ. П/ПЛЕН/ОБ. 2МГ+500МГ №30</td>
  <td class="MuiTableCell-root jss346 MuiTableCell-alignRight MuiTableCell-sizeSmall MuiTableCell-body">1</td>
  <td class="MuiTableCell-root jss346 MuiTableCell-alignLeft MuiTableCell-sizeSmall MuiTableCell-body"><a class="MuiTypography-root MuiLink-root MuiLink-underlineHover jss348 MuiTypography-colorPrimary"><svg class="MuiSvgIcon-root jss350" focusable="false" viewBox="0 0 24 24" aria-hidden="true" role="presentation"><path d="M18 17H6v-2h12v2zm0-4H6v-2h12v2zm0-4H6V7h12v2zM3 22l1.5-1.5L6 22l1.5-1.5L9 22l1.5-1.5L12 22l1.5-1.5L15 22l1.5-1.5L18 22l1.5-1.5L21 22V2l-1.5 1.5L18 2l-1.5 1.5L15 2l-1.5 1.5L12 2l-1.5 1.5L9 2 7.5 3.5 6 2 4.5 3.5 3 2v20z"></path></svg></a></td>
</tr>

等等……

我的代码：

chrome_options = webdriver.ChromeOptions()
chrome_options.add_argument("start-maximized")
driver = webdriver.Chrome(options=chrome_options)
driver.get(url)
XPATH = "//*[name()='svg' and contains(@class, 'jss350')]"
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//*[name()='svg' and contains(@class, 'jss350')]"))).click()
driver.quit()

Answer 1

您似乎在这里错误地使用了XPath —— 查询@name='svg' 将获得具有name 属性svg 的元素，而不是svg 类型的WebElements。

如果您想等待所有 svg 元素存在，您可以这样做：

WebDriverWait(driver, 20).until(EC.presence_of_all_elements_located((By.XPATH, "//svg[contains(@class, 'jss350')]")))

但是，您还希望遍历列表中的元素。您需要先找到所有元素，然后对其进行迭代。你可以试试下面的代码：

# Wait for all svg elements to be clickable
WebDriverWait(driver, 20).until(EC.presence_of_all_elements_located((By.XPATH, "//svg[contains(@class, 'jss350')]")))

# find list of svg elements
svg_elements = driver.find_elements_by_xpath("//svg[contains(@class, 'jss350')]")

# iterate the list and click each one
for element in svg_elements:
    element.click()

这将等待所有svg 元素存在，从页面中获取元素列表，迭代每个元素，然后单击它。