【发布时间】:2015-09-24 20:49:46
【问题描述】:
我正在尝试从其 URL 下载给定网站的 HTML。 执行此操作的代码位于异步任务中,与 UI 分开,并将 URL 传递给它,这工作正常。
设置了HttpClient,并创建了一个请求,但是在执行请求时,抛出了一个IOexception。 我不明白为什么会这样,因为 URL 是有效的,并且应用程序可以访问网络。
public class RetrieveData extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
String url = params[0];
Log.v("The URL is", url);
try {
HttpClient client = new DefaultHttpClient();
Log.v("Progress", "Got to HttpClient");
HttpGet request = new HttpGet(url);
Log.v("Progress", "Got to request");
HttpResponse response = client.execute(request);
Log.v("Progress", "Got to execute request");
String html = "";
Log.v("Progress", "Got to String html");
InputStream in = response.getEntity().getContent();
Log.v("Progress", "Got to InputStream");
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
str.append(line);
Log.v("The string is", str.toString());
}
in.close();
html = str.toString();
String TAG = "html extracted";
Log.v(TAG, html);
} catch (Exception IOexception) {
Log.v("IOexception ", "IOexception thrown in RetrieveData.java");
}
return null;
}
}
感谢所有帮助。
堆栈跟踪-
07-07 11:32:40.130 2168-2185/? W/System.err﹕ java.lang.IllegalStateException: Target host must not be null, or set in parameters. scheme=null, host=null, path=www.google.com
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at org.apache.http.impl.client.DefaultRequestDirector.determineRoute(DefaultRequestDirector.java:596)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:298)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:560)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:492)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:470)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at com.anapp.tpb.downloadhtml.RetrieveData.doInBackground(RetrieveData.java:43)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at com.anapp.tpb.downloadhtml.RetrieveData.doInBackground(RetrieveData.java:29)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at android.os.AsyncTask$2.call(AsyncTask.java:292)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at java.util.concurrent.FutureTask.run(FutureTask.java:237)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
07-07 11:32:40.130 2168-2185/? W/System.err﹕ at java.lang.Thread.run(Thread.java:818)
【问题讨论】:
-
你在调用什么 URL 和/或你可以发布错误(IOexception 值)
-
发布您的异常日志。在您的 catch 块中调用 IOexception.printStatckTrace() 以获取异常日志
-
会的。我尝试了各种常见的站点,它们抛出了异常,然后是一些更晦涩的站点,其中一些输出了 HTML。
-
默认情况下,尝试使用
Log的第二个参数来打印异常,而不是硬编码的字符串...Log将说明从哪里引发异常... StackTraces很好:-) -
将
http://添加到您的 url 调用中
标签: java android http ioexception