【问题标题】:Executing Native Query within JPA Repository Rest Resource在 JPA Repository Rest 资源中执行本机查询
【发布时间】:2018-01-21 00:58:55
【问题描述】:

我在将带有两个参数的自定义查询传递给 Spring 我的 Spring RepositoryRestResource 接口列表时遇到问题:

    @RepositoryRestResource(collectionResourceRel = "benefitplan", path = "benefitplan")
public interface BenefitPlanRepository extends PagingAndSortingRepository<BenefitPlan, Long> {
    BenefitPlan findTop1ByBenefitPackageCode(@Param("bpcode") String benefitPackageCode);
    BenefitPlan findByBenefitPackageCode(@Param("bpcode") String benefitPackageCode);
    BenefitPlan findTop1ByBenefitPackageCodeAndPlanStatus(@Param("bpcode") String benefitPackageCode, @Param("status") String status);
    @Query(value = 
            "SELECT b.BENEFIT_PLAN_ID FROM BENEFIT_PLAN b left join MEDICAL_PLAN m on b.MEDICAL_PLAN_ID = m.MEDICAL_PLAN_ID "
            + "left join RX_PLAN r on b.RX_PLAN_ID = r.RX_PLAN_ID WHERE r.MTV_RX_CD = ?2 and m.MTV_MEDICAL_CD = ?1"
            , nativeQuery = true)
    BenefitPlan findByMedicalPlanIdAndRxPlanId(@Param("medicalPlanId") String medicalPlanId, @Param("rxPlanId") String rxPlanId);
}

它的最后一个查询 findByMedicalPlanIdAndPlanId 给我带来了问题。其余的工作正常。我的错误是这样的:

出现意外错误(类型=内部服务器错误, 状态=500)。无法执行查询;嵌套异常是 org.hibernate.exception.GenericJDBCException:无法执行查询

【问题讨论】:

  • 你可以重命名那个方法名

标签: java spring hibernate rest spring-data-jpa


【解决方案1】:

试试

@Query(value = 
            "SELECT b.BENEFIT_PLAN_ID FROM BENEFIT_PLAN b left join MEDICAL_PLAN m on b.MEDICAL_PLAN_ID = m.MEDICAL_PLAN_ID "
            + "left join RX_PLAN r on b.RX_PLAN_ID = r.RX_PLAN_ID WHERE r.MTV_RX_CD = :rxPlanId and m.MTV_MEDICAL_CD = :medicalPlanId"
            , nativeQuery = true)
    BenefitPlan findByMedicalPlanIdAndRxPlanId(@Param("medicalPlanId") String medicalPlanId, @Param("rxPlanId") String rxPlanId);

如果您使用@Param,您希望使用命名参数,至少您应该在查询中使用它。如果它不起作用,我建议您在 db 客户端中执行查询以确保它起作用。

【讨论】:

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