【发布时间】:2019-07-06 08:45:20
【问题描述】:
我正在尝试比较 MS Access 中的两个数据数组 - 一个是从 API GET 生成的,另一个是从表的两列生成的。我正在使用双循环进行比较,我怀疑这不是最好的方法,但我仍在学习循环和数组的方法。我使用的代码如下:
Sub ParseList(ResCount As Long)
Dim db As DAO.Database
Dim rstConts As DAO.Recordset
Dim midstr As String, emailstr As String, Fname As String, Lname As String, SubStatus As String, echeck As String, Mecheck As String, ArrEcheck As String, ArrMecheck As String, MSub As String
Dim ArrResp() As String
Dim ArrConts() As Variant
Dim SubStart As Long, SubCount As Long, Fstart As Long, Fcount As Long, Lstart As Long, LCount As Long, Diffcount As Long, c As Long, i As Long, t As Long, y As Long, u As Long, v As Long
Dim IsSub As Boolean
Set db = CurrentDb
Udate = SQLDate(Now)
ReDim ArrResp(1 To ResCount, 1 To 4) As String
'This section parses a JSON response into an array
For i = 1 To ResCount
midstr = ""
emailstr = ""
x = InStr(t + 2, GetListStr, "}}") + 21
y = InStr(x + 1, GetListStr, "}}")
If y = 0 Then
Exit Sub
End If
midstr = Mid(GetListStr, x, y - x)
emailstr = Left(midstr, InStr(midstr, ",") - 2)
SubStart = InStr(midstr, "Status") + 9
SubCount = InStr(InStr(midstr, "Status") + 8, midstr, ",") - SubStart - 1
SubStatus = Replace(Mid(midstr, SubStart, SubCount), "'", "''")
Fstart = InStr(midstr, ":{") + 11
Fcount = InStr(InStr(midstr, ":{") + 11, midstr, ",") - (Fstart + 1)
Fname = Replace(Mid(midstr, Fstart, Fcount), "'", "''")
Lstart = InStr(midstr, "LNAME") + 8
LCount = InStr(InStr(midstr, "LNAME") + 8, midstr, ",") - (Lstart + 1)
Lname = Replace(Mid(midstr, Lstart, LCount), "'", "''")
If SubStatus = "subscribed" Then
MSub = "True"
Else
MSub = "False"
End If
ArrResp(i, 1) = emailstr
ArrResp(i, 2) = MSub
ArrResp(i, 3) = Fname
ArrResp(i, 4) = Lname
t = y
Next i
'This section grabs two columns from a database table and adds them to a second array
Set rstConts = CurrentDb.OpenRecordset("SELECT Primary_Email, EMailings FROM TBLContacts")
rstConts.MoveLast
rstConts.MoveFirst
c = rstConts.RecordCount
ReDim ArrConts(1 To c) As Variant
ArrConts = rstConts.GetRows(c)
'This loops through the JSON response array, and when it finds a matching value in the Table array it checks if a second value in the table array matches or not
For u = 1 To ResCount
Debug.Print u
echeck = ArrResp(u, 1)
Mecheck = ArrResp(u, 2)
For v = 0 To c
If ArrConts(0, v) = "" Then
Else
ArrEcheck = ArrConts(0, v)
ArrMecheck = ArrConts(1, v)
If ArrEcheck = echeck Then
If ArrMecheck = Mecheck Then
Debug.Print echeck & "Match"
Else
Debug.Print echeck & "No Match"
End If
End If
End If
Next v
Next u
MsgBox "Done"
End Sub
上面的代码根本没有完成,并且 msgbox 永远不会显示。接近尾声的 debug.print 行只到 1,我不知道为什么。如果我从第二个循环部分中删除条件:
If ArrConts(0, v) = "" Then
Else
ArrEcheck = ArrConts(0, v)
ArrMecheck = ArrConts(1, v)
If ArrEcheck = echeck Then
If ArrMecheck = Mecheck Then
Debug.Print echeck & "Match"
Else
Debug.Print echeck & "No Match"
End If
End If
End If
然后我可以成功完成主循环,并收到“完成”消息。但是我一直无法确定第二个循环没有正确完成的原因,我被卡住了。
【问题讨论】:
-
这是在 Access 中吗?您可以在 SQL 语句中使用 JSON 响应数组吗?
Join将加入数组,所以你可以说where field in (" & join(arrJson,",") & ")" -
您是否单步 (F8) 通过您的代码?如果数据很大,您可以生成其中的一小部分并单步执行吗?
-
这是在 Access 中 - @Nathan_Sav 你能扩展这个加入选项吗?我以前没有遇到过。我试过用 F8 但它不起作用,这很奇怪。
-
是的,我在帖子里有,所以如果你的 JSON 数组包含“Lookup1”、“lookup2”、“Lookup3”,那么你想让它成为 SQL where 条件,所以你可以说
select * from table where field in (" & join(arrJSON,",") & ")"会给你select * from table where field in ("Lookup1","lookup2","Lookup3") -
请用proper error handling 包装您的整个处理过程,因为应该提出一个消息。
标签: arrays loops ms-access vba