根据用户输入 powershell 过滤 JSON

Question

我有用逗号分隔的用户输入，我正在使用 split 函数来获取不同的值。我有一个以 JSON 格式返回一些数据的 API。我想根据用户输入过滤来自 API Json 的数据

Powershell 代码

#Get Input data
$GetIds = Read-Host -Prompt 'Enter Ids:'

#Example 1,2
#If they enter 1,2, I want results data of John and Mark
#API Call Data
$json = @'
{  
    "results": [
        {
            "id": "1", 
             "name": "John",           
        }, 
        {
             "id": "2", 
             "name": "Mark",  
        },
        {
             "id": "3", 
             "name": "Rachel",  
        }
    ]
}
'@

$Obj = ConvertFrom-Json $json

#Split by comma

$userInputData = -split $GetIds 

#Filter json with $userInputData 
$FilteredData = $json | Where-Object { $_.id -eq #loop through $userInputData }

我希望过滤后的数据返回由 userInput 数据过滤的 $json。谢谢

Answer 1

首先，如果您想用逗号 (,) 分割，请使用 -split operator 的 binary 形式 - unary 形式使用 空格分割 仅限。

# Sample user input
$GetIds = '1, 2'

# Split by ",", remove surrounding whitespace, convert to integers.
# For brevity, there's no error handling her, 
# so an empty / blank input wouldn't be interpreted as id 0, 
# and input such as `'1 2'` (no comma) would break.
[int[]] $userInputData = ($GetIds -split ',').Trim()

接下来，您必须使用Where-Object 过滤$Obj，即ConvertFrom-Json 将您的JSON 文本解析成的自定义对象图，而不是原始JSON：

$filteredData = $Obj.results | Where-Object id -in $userInputData

-in operator 允许您测试 LHS 是否是 RHS 阵列的一部分。

---

把它们放在一起：

注意：您的示例 JSON 在技术上是无效的，因为 .results 对象中最后一个属性后面的尾随逗号，我在下面更正了。在 PowerShell [Core] v6+ 中，ConvertFrom-Json 甚至可以接受无效的 JSON，但在 Windows PowerShell 中则不行。

# Sample user input, in lieu of the Read-Host call.
$GetIds = '1, 2'

# Split by ",", remove surrounding whitespace, convert to integers.
# For brevity, there's no error handling her, 
# so an empty / blank input wouldn't be interpreted as id 0, 
# and input such as `'1 2'` (no comma) would break.
[int[]] $userInputData = ($GetIds -split ',').Trim()

$Obj = ConvertFrom-Json @'
{  
    "results": [
        {
            "id": "1", 
             "name": "John"
        }, 
        {
             "id": "2", 
             "name": "Mark"
        },
        {
             "id": "3", 
             "name": "Rachel"
        }
    ]
}
'@

$filteredData = $Obj.results | Where-Object id -in $userInputData

# Output the matching objects
$filteredData

以上产出：

id name
-- ----
1  John
2  Mark

Answer 2

怎么样...

# You can split on the read
$GetIds = (Read-Host -Prompt 'Enter Ids') -split (',')
# Results
<#
1
2
#>

# Your JSON string was not valid
<#
Error: Parse error on line 4:
...     "name": "John",     },      {           "id": "2",
----------------------^
Expecting 'STRING', got '}'
#>

# Corrected, notice the removed comma after the names 
$json = @'
{  
    "results": [
        {
            "id": "1", 
             "name": "John"           
        }, 
        {
             "id": "2", 
             "name": "Mark"  
        },
        {
             "id": "3", 
             "name": "Rachel"  
        }
    ]
}
'@

$Obj = $json | ConvertFrom-Json

不需要这个...

$userInputData = -split $GetIds 

...因为拆分是在读取上

# Filter json with $userInputData 
$Obj.results | 
Where-Object id -in $GetIds
# Results
<#
id name
-- ----
1  John
2  Mark
#>