刚刚在 Symfony 3 上制作了这个，发现它与这里已经发布的有点不同，所以我认为它值得分享。
我刚刚制作了一个通用数据转换器，可以轻松地在所有表单类型中重复使用。你只需要传入你的表单类型就可以了。无需创建自定义表单类型。
首先让我们看一下数据转换器：
<?php
namespace AppBundle\Form;
use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Component\Form\DataTransformerInterface;
use Symfony\Component\Form\Exception\TransformationFailedException;
/**
* Class EntityHiddenTransformer
*
* @package AppBundle\Form
* @author Francesco Casula <fra.casula@gmail.com>
*/
class EntityHiddenTransformer implements DataTransformerInterface
{
/**
* @var ObjectManager
*/
private $objectManager;
/**
* @var string
*/
private $className;
/**
* @var string
*/
private $primaryKey;
/**
* EntityHiddenType constructor.
*
* @param ObjectManager $objectManager
* @param string $className
* @param string $primaryKey
*/
public function __construct(ObjectManager $objectManager, $className, $primaryKey)
{
$this->objectManager = $objectManager;
$this->className = $className;
$this->primaryKey = $primaryKey;
}
/**
* @return ObjectManager
*/
public function getObjectManager()
{
return $this->objectManager;
}
/**
* @return string
*/
public function getClassName()
{
return $this->className;
}
/**
* @return string
*/
public function getPrimaryKey()
{
return $this->primaryKey;
}
/**
* Transforms an object (entity) to a string (number).
*
* @param object|null $entity
*
* @return string
*/
public function transform($entity)
{
if (null === $entity) {
return '';
}
$method = 'get' . ucfirst($this->getPrimaryKey());
// Probably worth throwing an exception if the method doesn't exist
// Note: you can always use reflection to get the PK even though there's no public getter for it
return $entity->$method();
}
/**
* Transforms a string (number) to an object (entity).
*
* @param string $identifier
*
* @return object|null
* @throws TransformationFailedException if object (entity) is not found.
*/
public function reverseTransform($identifier)
{
if (!$identifier) {
return null;
}
$entity = $this->getObjectManager()
->getRepository($this->getClassName())
->find($identifier);
if (null === $entity) {
// causes a validation error
// this message is not shown to the user
// see the invalid_message option
throw new TransformationFailedException(sprintf(
'An entity with ID "%s" does not exist!',
$identifier
));
}
return $entity;
}
}
所以想法是通过传递对象管理器、要使用的实体以及字段名称来调用它，以获取实体 ID。
基本上是这样的：
new EntityHiddenTransformer(
$this->getObjectManager(),
Article::class, // in your case this would be FoodAnalytics\Recipe::class
'articleId' // I guess this for you would be recipeId?
)
现在让我们把它们放在一起。我们只需要表单类型和一些 YAML 配置就可以了。
<?php
namespace AppBundle\Form;
use AppBundle\Entity\Article;
use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\Form\Extension\Core\Type\HiddenType;
use Symfony\Component\Form\Extension\Core\Type\SubmitType;
use Symfony\Component\OptionsResolver\OptionsResolver;
/**
* Class JustAFormType
*
* @package AppBundle\CmsBundle\Form
* @author Francesco Casula <fra.casula@gmail.com>
*/
class JustAFormType extends AbstractType
{
/**
* @var ObjectManager
*/
private $objectManager;
/**
* JustAFormType constructor.
*
* @param ObjectManager $objectManager
*/
public function __construct(ObjectManager $objectManager)
{
$this->objectManager = $objectManager;
}
/**
* @return ObjectManager
*/
public function getObjectManager()
{
return $this->objectManager;
}
/**
* {@inheritdoc}
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('article', HiddenType::class)
->add('save', SubmitType::class);
$builder
->get('article')
->addModelTransformer(new EntityHiddenTransformer(
$this->getObjectManager(),
Article::class,
'articleId'
));
}
/**
* {@inheritdoc}
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => 'AppBundle\Entity\MyEntity',
]);
}
}
然后在您的services.yml 文件中：
app.form.type.article:
class: AppBundle\Form\JustAFormType
arguments: ["@doctrine.orm.entity_manager"]
tags:
- { name: form.type }
在你的控制器中：
$form = $this->createForm(JustAFormType::class, new MyEntity());
$form->handleRequest($request);
就是这样:-)