无法在 powershell 中将自定义对象导出到 CSV

Question

我已经编写了 powershell 脚本来生成 IIS 信息到 CSV。

$bindingip = Get-WmiObject -Namespace root\webadministration -Class sslbinding2 | Select-Object - 
Property PSComputerName,IPAddress
$sitedetails = Get-Website | Select-Object -Property Name,ID,State
$report = New-Object psobject
$report | Add-Member -MemberType NoteProperty -Name "Hostname" -Value $bindingip.PSComputerName
$report | Add-Member -MemberType NoteProperty -Name "IPAddress" -Value $bindingip.IPAddress
$report | Add-Member -MemberType NoteProperty -Name "Site Name" -Value $sitedetails.name
$report | Add-Member -MemberType NoteProperty -Name "ID" -Value $sitedetails.id
$report | Add-Member -MemberType NoteProperty -Name "State" -Value $sitedetails.state
$report | Export-Csv C:\content.csv -NoTypeInformation

CSV 的输出：

Hostname         IPAddress        Site Name       ID               State
System.Object[]  System.Object[]  System.Object[] System.Object[]  System.Object[]

我是否需要在代码中添加任何内容才能获得准确的输出，有人可以帮忙吗？

Answer 1

正如Abraham 和Ash 在他们的cmets 中指出的那样，变量$bindingip 和$sitedetails 的属性值是一个数组而不是一个字符串。这就是为什么当您导出报告时会得到 object type 而不是它的实际值。

您可以通过以下方式看到这一点：

$bindingip.PSComputerName.GetType()

这会返回如下内容：

IsPublic IsSerial Name        BaseType    
-------- -------- ----        --------    
True     True     Object[]    System.Array

但是，如果您只选择数组 PSComputerName 上的第一个元素

$bindingip.PSComputerName[0].GetType()

你会看到：

IsPublic IsSerial Name        BaseType     
-------- -------- ----        --------     
True     True     String      System.Object

解决方法是通过使用Out-String 或将数组元素与分隔符（即-join '//'）连接起来，将值转换为多行字符串。

$bindingip = Get-WmiObject -Namespace root\webadministration -Class sslbinding2
$sitedetails = Get-Website

# Like this (thanks mklement0):
$report = [pscustomobject]@{
    Hostname = "$($bindingip.PSComputerName)"
    IPAddress = "$($bindingip.IPAddress)"
    'Site Name' = "$($sitedetails.name)"
    ID = "$($sitedetails.id)"
    State = "$($sitedetails.state)"
}

# Or like this:
$report = [pscustomobject]@{
    Hostname = ($bindingip.PSComputerName | Out-String).trim()
    IPAddress = ($bindingip.IPAddress | Out-String).trim()
    'Site Name' = ($sitedetails.name | Out-String).trim()
    ID = ($sitedetails.id | Out-String).trim()
    State = ($sitedetails.state | Out-String).trim()
}

# Or like this:
$report = [pscustomobject]@{
    Hostname = $bindingip.PSComputerName -join '//'
    IPAddress = $bindingip.IPAddress -join '//'
    'Site Name' = $sitedetails.name -join '//'
    ID = $sitedetails.id -join '//'
    State = $sitedetails.state -join '//'
}

$report | Export-Csv C:\content.csv -NoTypeInformation

编辑

这也可以，这是我认为mklement0 建议的。它将根据属性的值为每个元素创建一个新对象：

$compName = $bindingip.PSComputerName
$ipAddr = $bindingip.IPAddress
$name = $sitedetails.name
$id = $sitedetails.id
$state = $sitedetails.state

$top = ($compName.Count,$ipAddr.Count,$name.Count,$id.Count,$state.Count | Measure-Object -Maximum).Maximum

$report = for($i = 0;$i -lt $top;$i++)
{
    [pscustomobject]@{
        Hostname = $compName[$i]
        IPAddress = $ipAddr[$i]
        'Site Name' = $name[$i]
        ID = $id[$i]
        State = $state[$i]
}

$report | Export-Csv...

Answer 2

除了 Santiago 的 very thorough and excellent answer，在我看来，我们只是将一个数组的对象与另一个数组组合以产生所有可能的组合。我可能会执行以下操作来完成此操作。

$bindingip = @(
    [PSCustomObject]@{
        PSComputerName = 'Public1'
        IPAddress      = '192.168.0.1'
    },
    [PSCustomObject]@{
        PSComputerName = 'Public1'
        IPAddress      = '127.0.0.1'
    }
)

$siteDetails = @(
    [PSCustomObject]@{
        Name  = 'site 1'
        Id    = 'site1'
        State = 'up'
    },
    [PSCustomObject]@{
        Name  = 'site 2'
        Id    = 'site2'
        State = 'down'
    }
)    

$combined = foreach ($ip in $bindingip) {
    foreach ($details in $siteDetails) {
        $out = [ordered]@{}
        $ip.psobject.properties | ForEach-Object {
            $out[$_.Name] = $_.Value
        }
        $details.psobject.properties | ForEach-Object {
            $out[$_.Name] = $_.Value
        }

        [pscustomobject]$out
    }
}

$combined | Format-Table

输出

PSComputerName IPAddress   Name   Id    State
-------------- ---------   ----   --    -----
Public1        192.168.0.1 site 1 site1 up
Public1        192.168.0.1 site 2 site2 down
Public1        127.0.0.1   site 1 site1 up
Public1        127.0.0.1   site 2 site2 down

可以将其包装在一个函数中以实现可重用性

function Combine-ObjectsFromTwoArrays {
    param (
        [array]$array1,
        [array]$array2
    )

    foreach ($obj1 in $array1) {
        foreach ($obj2  in $array2) {
            $out = [ordered]@{}
            $obj1.psobject.properties | ForEach-Object {
                $out[$_.Name] = $_.Value
            }
            $obj2.psobject.properties | ForEach-Object {
                $out[$_.Name] = $_.Value
            }

            [pscustomobject]$out
        }
    }
}