是否可以使用 jq 来 sort_by 然后 sort_by 再次按子项目

Question

我有以下 json：

[
  {
    "SG": [
      {
        "Id": "17",
        "GroupName": "fistGN",
        "Permissions": [
          {
            "Port": 80,
            "Protocol": "tcp"
          },
          {
            "Port": 8080,
            "Protocol": "tcp"
          },
          {
            "Port": 5080,
            "Protocol": "tcp"
          }
        ]
      },
      {
        "Id": "1",
        "GroupName": "secondGN",
        "Permissions": [
          {
            "Port": 80,
            "Protocol": "tcp"
          },
          {
            "Port": 8080,
            "Protocol": "tcp"
          },
          {
            "Port": 5080,
            "Protocol": "tcp"
          }
        ]
      }
    ]
  }
]

是否可以使用单个命令按 GroupName 排序，然后按权限端口对每个组进行排序？

这是我正在尝试做的，但没有按预期工作：

jq -s -S '.[].SG |= sort_by(.GroupName, .Permissions[].Port)' myfile.json

Answer 1

jq解决方案：

jq '.[0].SG |= (map(.Permissions |= sort_by(.Port)) | sort_by(.GroupName))' myfile.json

• (map(.Permissions |= sort_by(.Port)) | sort_by(.GroupName)) - 用于分隔 2 个排序操作的复合表达式：
  • map(.Permissions |= sort_by(.Port)) - 获取一个新数组，其中每个内部 .Permissions 数组按键 "Port" 值排序
  • sort_by(.GroupName) - 按 "GroupName" 键对 SG 数组项进行排序

---

输出：

[
  {
    "SG": [
      {
        "Id": "17",
        "GroupName": "fistGN",
        "Permissions": [
          {
            "Port": 80,
            "Protocol": "tcp"
          },
          {
            "Port": 5080,
            "Protocol": "tcp"
          },
          {
            "Port": 8080,
            "Protocol": "tcp"
          }
        ]
      },
      {
        "Id": "1",
        "GroupName": "secondGN",
        "Permissions": [
          {
            "Port": 80,
            "Protocol": "tcp"
          },
          {
            "Port": 5080,
            "Protocol": "tcp"
          },
          {
            "Port": 8080,
            "Protocol": "tcp"
          }
        ]
      }
    ]
  }
]