如何对mysql结果进行排序？

Question

表：

 id        title

1.         php is a good language.
2.         Java is a good language
3.         All language are good
4.         Php,Java both good language
5.         Php is good but Java is not

问题

字符串：$#

$string = "php Java language"

结果顺序

php ,Java both  good language
-------------------------
php is good Java is not

-------------------------
php is good language 
---------------------------
Java is good language
------------------------
all language are good

我不知道如何通过字符串中匹配的单词数来获得订单列表。

如果你能解释一下查询，那就太好了。

谢谢。

Answer 1

然后将您的字符串转换为 JSON 数组

SELECT test.id, test.tittle
FROM test
LEFT JOIN JSON_TABLE(@criteria, 
                     "$[*]" COLUMNS (word VARCHAR(255) PATH "$")) jsontable ON LOCATE (jsontable.word, test.tittle)
GROUP BY test.id, test.tittle
ORDER BY SUM(jsontable.word IS NOT NULL) DESC

@criteria 是上面提到的 JSON 数组的占位符。

当然，您可以将条件作为空格分隔的字符串提供，并在查询中使用字符串函数将其转换为 JSON。

---

不使用 JSON 的版本：

WITH RECURSIVE
cte AS (SELECT test.id, 
               test.tittle, 
               0 amount, 
               TRIM(TRIM(LEADING SUBSTRING_INDEX(@criteria, ' ', 1) FROM @criteria)) criteria, 
               SUBSTRING_INDEX(@criteria, ' ', 1) token
        FROM test
        UNION ALL
        SELECT id, 
               tittle,
               amount + (LOCATE(token, tittle) > 0),
               TRIM(TRIM(LEADING token FROM criteria)),
               SUBSTRING_INDEX(criteria, ' ', 1)
        FROM cte
        WHERE TRIM(criteria) != '' )
SELECT id, tittle
FROM cte
GROUP BY id, tittle
ORDER BY MAX(amount) DESC;

https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=3ab611ed7429e23be2abfcb8b0186e6d