PHP添加重复的数组答案

【问题标题】：PHP add arrays with duplicatesPHP添加重复的数组
【发布时间】：2014-04-12 16:37:57
【问题描述】：

现在，我有一种方法可以将两个关联数组的关联数组与删除的重复值合并。代码如下：

//$mergedProp will output the final merged arrays
$mergedProp = array(array());
$prop1 = Array ( 
                [1] => Array ( [property_code] => CODE-01 [street] => 100 Fake Street 
                                [city] => Las Vegas [state] => NV [zip] => (no results) 
                                [county] => (no results) [id] => 6 ) 
                [2] => Array ( [property_code] => CODE-02 [street] => 200 Fake St 
                                [city] => Fake City [state] => AR [zip] => 45532 
                                [county] => Union [id] => 3 ) ) ;

$prop2 = Array ( 
                [1] => Array ( [property_code] => CODE-03 [street] => 1140 Fake Street 
                                [city] => Detroit [state] => MI [zip] => 45224 
                                [county] => Hamilton [id] => 3 ) 
                [2] => Array ( [property_code] => CODE-02 [street] => 200 Fake St 
                                [city] => Fake City [state] => AR [zip] => 45532 
                                [county] => Union [id] => 12 ) ) 

$arrayMerged = array_merge($prop1, $prop2);
$arrayUnique = array();

foreach ($arrayMerged as $row) {
  $code = $row['property_code'];
  if (!isset($arrayUnique[$code])) {
    $arrayUnique[$code] = array();
  }
    $arrayUnique[$code] = array_merge($arrayUnique[$code], $row);
}

//Sorts the array
ksort($arrayUnique);

$i = 1;
$newGrid = array();
foreach($arrayUnique as $r)
$newGrid[$i++] = $r;

$countDuplicates = count($arrayMerged) - count($newGrid);
$mergedProp = $newGrid;

上面的输出：

Array ( 
    [1] => Array ([property_code] => CODE-01 [street] => 100 Fake Street 
                    [city] => Las Vegas [state] => NV [zip] => (no results) 
                    [county] => (no results) [id] => 6 ) 
    [2] => Array ([property_code] => CODE-03 [street] => 1140 Fake Street 
                    [city] => Detroit [state] => MI [zip] => 45224 
                    [county] => Hamilton [id] => 3 ) 
    [3] => Array ([property_code] => CODE-02 [street] => 200 Fake St 
                    [city] => Fake City [state] => AR [zip] => 45532 
                    [county] => Union [id] => 12 ) )

我希望预期的输出低于：

Array ( 
    [1] => Array ([property_code] => CODE-01 [street] => 100 Fake Street 
                    [city] => Las Vegas [state] => NV [zip] => (no results) 
                    [county] => (no results) [id] => 6 ) 
    [2] => Array ([[property_code] => CODE-02 [street] => 200 Fake St 
                    [city] => Fake City [state] => AR [zip] => 45532 
                    [county] => Union [id] => 3 ) 
    [3] => Array ([property_code] => CODE-03 [street] => 1140 Fake Street 
                    [city] => Detroit [state] => MI [zip] => 45224 
                    [county] => Hamilton [id] => 3 )                    
    [4] => Array ([property_code] => CODE-02 [street] => 200 Fake St 
                    [city] => Fake City [state] => AR [zip] => 45532 
                    [county] => Union [id] => 12 ) )

我怎样才能让它保留重复的值呢？我基本上希望输出在 1 个数组中包含 $prop1 和 $prop2。

【问题讨论】：

不确定你的意思，当你做$arrayMerged = array_merge($prop1, $prop2);时你已经知道了。
显示预期的输出。
@AbraCadaver 我回去并包含了预期的输出

标签： php arrays multidimensional-array

【解决方案1】：

也许 PHP 函数 array_intersect_assoc() 会有所帮助 - 它会给你数组的差异。

http://php.net/manual/en/function.array-intersect-assoc.php

【讨论】：

【解决方案2】：

对于您所展示的内容，您只需按原样合并它们：

$arrayMerged = array_merge($prop1, $prop2);

就是这样。

【讨论】：