在 Python 中按特定的相同列表值对列表进行分组

Question

谁能提供有关如何按某些列表元素查找和分组列表的建议？

下面是一个示例，它通过比较所有列表元素在子列表中查找和分组相同的值...

在列表中查找和分组相同值的工作示例：

L = #List of Vectors

# Example L[0] = [8.999999590709139, 164.00000059986633, 152.00000160567942]

d = defaultdict(list) # Group by same Vectors

for item in L:
    d[tuple(item)].append(item)

sv = sorted(d[x] for x in d)

print "No of same values found =”, len(sv) 

上面的工作示例考虑了列表中的所有项目进行比较，但是如何考虑仅通过列表的前三个项目来查找和分组相同的项目，同时保持列表完整？

# Example L2[0] = [8.999999590709139, 164.00000059986633, 152.00000160567942, "Q","W","E","R","T","Y","3.14"]

# Example L2[1] = [8.999999590709139, 164.00000059986633, 152.00000160567942, "A","S","D","F","G","H","J"]

# len(L2[0]) = 10

# Find and group lists with same L2[i][0], L2[i][1], L2[i][2] values...

# Desired output - sortedlist = [[[1,2,3,"a","b","c"],[1,2,3,"d","e","f"]],[[3,4,5,"a","b","c"],[3,4,5,"d","e","f"]]]

#print sortedlist returns [[[1, 2, 3, 'a', 'b', 'c'], [1, 2, 3, 'd', 'e', 'f']], [[3, 4, 5, 'a', 'b', 'c'], [3, 4, 5, 'd', 'e', 'f']]]

#print sortedlist[1] returns [[3, 4, 5, 'a', 'b', 'c'], [3, 4, 5, 'd', 'e', 'f']]

#print sortedlist returns [1][2] [3, 4, 5, 'a', 'b', 'c']

任何帮助或指点将不胜感激......

Answer 1

感谢jzk2...

 from collections import defaultdict

 d = defaultdict(list)

for item in L:
    d[tuple(item[:3])].append(item)

sortedL = sorted(d[x] for x in d)