PHP：如何按数据库的姓氏和距离排序

Question

我很难弄清楚。我可能只是忽略了它，但我想有人可以帮我做什么。我需要通过单击两个单独的单选按钮按姓氏和距离进行排序。这一切都将在一个半小时内完成，我是使用 PHP 排序的新手。我在这里搜索过，但没有找到与我正在寻找的内容相关的任何答案。任何帮助将不胜感激。

PHP：

<tr><th>First Name</th><th>Last Name</th><th>Email</th><th>Distance</th></tr>
    <?php  
    include('includes/database/dbc.php');
    $sql = "SELECT * FROM runner ORDER BY 'lname'";
    $result = mysql_query($sql) or die('Error! '.mysql_error());
    if(mysql_num_rows($result)==0) {
    echo "<tr><td colspan='4'>Sorry, no lists are available today. Check back soon!</td></tr>";
    }
    while($row=mysql_fetch_assoc($result)) {
    echo '<tr><td>'.$row['fname'].'</td>';
    echo '<td>'    .$row['lname'].'</td>';
    echo '<td>'    .$row['email'].'</td>';
    echo '<td>'    .$row['Distance'].'</td></tr>';
    }
    ?>
    <?php if(isset($_POST['submit_sort'])){
    $radio = $_POST['submit_sort'];
    if($radio =='fname'){
        $select ="SELECT fname, address1 FROM runner ORDER BY lname";}elseif($radio =='address1'){
        $select ="SELECT fname, address1 FROM runner ORDER BY address1";}       
    $result = mysql_query($lrconnect,$select)or die("Invalid query: ".mysql_error($lrconnect));
    }
    ?>

HTML：

<div id="sort">
        <form class="form2" action="submit_sort">
            <input type="radio" name="sort" value="lname" id="lnamesort" >Sort By Last Name
            <br>
            <input type="radio" name="sort" value="distance" id="distancesort">Sort By Distance
        </form>
</div>

Answer 1

您的代码中有一些错误。根据您的需要，它应该如下所示：

HTML:-

 <div id="sort">
            <form class="form2" action="your_action" method="POST">
                <input type="radio" name="sort" value="lname" id="lnamesort" >Sort By Last Name
                <br>
                <input type="radio" name="sort" value="distance" id="distancesort">Sort By Distance
                <input type="submit" name="search" value="search">
            </form>
    </div>

PHP:-

<?php 
if(isset($_POST['sort'])){
    $radio = $_POST['sort'];
    if($radio =='lname'){
        $select ="SELECT fname, address1 FROM runner ORDER BY lname";
    }elseif($radio =='distance'){
        $select ="SELECT fname, address1 FROM runner ORDER BY distance";
    }       
    $result = mysql_query($lrconnect,$select)or die("Invalid query: ".mysql_error($lrconnect));
}
?>