【问题标题】:Sorting Table with javascript用javascript排序表
【发布时间】:2021-11-11 06:20:16
【问题描述】:

我有一个简单的 HTML 表格,如下所示:

    <table id="myTable">
<thead>
  <tr>
    <th class="pointer" onClick="sortTable()">Number</th>
    <th>Example3</th>
    <th>Example2</th>
    <th>Example1</th>
  </tr>
</thead>
<tbody>
  <tr>
    <td>101</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-01</td>
  </tr>
  <tr>
    <td>102</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-02</td>
  </tr>
</tbody>
  
</table>

以及用于在 javascript 中对该表进行排序的函数,但它不起作用。我想按列号降序对表格进行排序。如何解决这个问题?我还想在列名旁边添加一个箭头 点击箭头调用函数

function sortTable() {
  var table, rows, switching, i, x, y, shouldSwitch;
  table = document.getElementById("myTable");
  switching = true;
  /*Make a loop that will continue until
  no switching has been done:*/
  while (switching) {
    //start by saying: no switching is done:
    switching = false;
    rows = table.rows;
    /*Loop through all table rows (except the
    first, which contains table headers):*/
    for (i = 1; i < (rows.length - 1); i++) {
      //start by saying there should be no switching:
      shouldSwitch = false;
      /*Get the two elements you want to compare,
      one from current row and one from the next:*/
      x = rows[i].getElementsByTagName("TD")[0];
      y = rows[i + 3].getElementsByTagName("TD")[0];
      //check if the two rows should switch place:
      if (Number(x.innerHTML) > Number(y.innerHTML)) {
        //if so, mark as a switch and break the loop:
        shouldSwitch = true;
        break;
      }
    }
    if (shouldSwitch) {
      /*If a switch has been marked, make the switch
      and mark that a switch has been done:*/
      rows[i].parentNode.insertBefore(rows[i + 3], rows[i]);
      switching = true;
    }
  }
}

【问题讨论】:

    标签: javascript sorting


    【解决方案1】:

    为什么用 rows[i + 3] 而不是 rows[i + 1] 切换? 为什么要打破循环,直到结束才继续?

    function sortTable() {
      var table, rows, switching, x, y;
      table = document.getElementById("myTable");
      /*Make a loop that will continue until
      no switching has been done:*/
      do {
        //start by saying: no switching is done:
        switching = false;
        rows = table.rows;
        /*Loop through all table rows (except the
        first, which contains table headers):*/
        for (var i = 1; i < (rows.length - 1); i++) {
          //start by saying there should be no switching:
          /*Get the two elements you want to compare,
          one from current row and one from the next:*/
          x = rows[i].getElementsByTagName("TD")[0];
          y = rows[i + 1].getElementsByTagName("TD")[0];
          //check if the two rows should switch place:
          if (Number(x.innerHTML) > Number(y.innerHTML)) {
            //if so, mark as a switch
            switching = true;
            rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
            rows = table.rows;
          }
        }
        // run until no switches
      } while (switching)
    }
    <table id="myTable">
    <thead>
      <tr>
        <th class="pointer" onClick="sortTable()">Number</th>
        <th>Example3</th>
        <th>Example2</th>
        <th>Example1</th>
      </tr>
    </thead>
    <tbody>
      <tr>
        <td>101</td>
        <td>TOM</td>
        <td>Not Working</td>
        <td>AUTOMAT-01</td>
      </tr>
      <tr>
        <td>102</td>
        <td>TOM</td>
        <td>Not Working</td>
        <td>AUTOMAT-02</td>
      </tr>
      <tr>
        <td>100</td>
        <td>TOM</td>
        <td>Not Working</td>
        <td>AUTOMAT-00</td>
      </tr>
    </tbody>
      
    </table>

    【讨论】:

      【解决方案2】:

      如果您对您所在的页面 (https://www.w3schools.com/howto/howto_js_sort_table.asp) 多阅读一些内容,您可以找到这个问题的答案。

      function sortTable(n) {
        var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
        table = document.getElementById("myTable");
        switching = true;
        // Set the sorting direction to ascending:
        dir = "asc";
        /* Make a loop that will continue until
        no switching has been done: */
        while (switching) {
          // Start by saying: no switching is done:
          switching = false;
          rows = table.rows;
          /* Loop through all table rows (except the
          first, which contains table headers): */
          for (i = 1; i < (rows.length - 1); i++) {
            // Start by saying there should be no switching:
            shouldSwitch = false;
            /* Get the two elements you want to compare,
            one from current row and one from the next: */
            x = rows[i].getElementsByTagName("TD")[n];
            y = rows[i + 1].getElementsByTagName("TD")[n];
            /* Check if the two rows should switch place,
            based on the direction, asc or desc: */
            if (dir == "asc") {
              if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) {
                // If so, mark as a switch and break the loop:
                shouldSwitch = true;
                break;
              }
            } else if (dir == "desc") {
              if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) {
                // If so, mark as a switch and break the loop:
                shouldSwitch = true;
                break;
              }
            }
          }
          if (shouldSwitch) {
            /* If a switch has been marked, make the switch
            and mark that a switch has been done: */
            rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
            switching = true;
            // Each time a switch is done, increase this count by 1:
            switchcount ++;
          } else {
            /* If no switching has been done AND the direction is "asc",
            set the direction to "desc" and run the while loop again. */
            if (switchcount == 0 && dir == "asc") {
              dir = "desc";
              switching = true;
            }
          }
        }
      }
          <table id="myTable">
      <thead>
        <tr>
          <th class="pointer" onClick="sortTable(0)">Number</th>
          <th>Example3</th>
          <th>Example2</th>
          <th>Example1</th>
        </tr>
      </thead>
      <tbody>
        <tr>
          <td>101</td>
          <td>TOM</td>
          <td>Not Working</td>
          <td>AUTOMAT-01</td>
        </tr>
        <tr>
          <td>102</td>
          <td>TOM</td>
          <td>Not Working</td>
          <td>AUTOMAT-02</td>
        </tr>
      </tbody>
        
      </table>

      这里关联的小提琴:https://jsfiddle.net/Louf0sc7/

      【讨论】:

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