php - Laravel：如何在从下拉列表中选择更改后加载 Ajax 数据？

Question

我想在从文本框中的下拉列表中选择一个值后加载一些 ajax 数据。

例如：从下拉列表中选择教师后，应加载教师剩余学分和 credit_taken 值。 ajax 怎么做？

注意：这里的教师值是从 Ajax 中的另一个下拉列表中选择的

<script>
      $('#teacher').on('change',function(e){            
           var teach_id = $('#teacher option:selected').attr('value');

             var info=$.get("{{url('ajax-teach')}}",{teach_id:teach_id});
               info.done(function(data){     
                  $.each(data,function(index,subcatObj){

               /// Here will  be the loaded code   ///

                    });                    
        });

        info.fail(function(){
          alert('ok');
        });
       });
    </script>

这是我的控制器：

Route::get('ajax-teach',function(Request $request){ 
        $teach_id = $request::input(['teach_id']);          
        $teachers=\App\Teacher::where('teacher_id','=',$teach_id)->get();
        return Response::json($teachers);   
});

这是查看页面：

<div class="form-group">
    <label for="">Teacher</label>
    <select class="form-control input-sm" required name="teacher_id" id="teacher" >
    <option value=""></option>
    </select>
</div> 


<div class="form-group">
  <label>Credit to be Taken</label>         
  <input type="text" name="credit_taken" id="credit_taken" class="form-control" required placeholder="Credit to be Taken">
</div>

<div class="form-group">
  <label>Remaining Credit</label>         
  <input type="text" name="remaining_credit" class="form-control" required placeholder="Remaining Credit">
</div>

Answer 1

在您的路线中 (routes/web.php)

Route::get( '/ajaxteach', array(
    'as' => 'ajaxteach',
    'uses' => 'TeachController@get_teach'
) );

在您的控制器中 (app/Http/Controllers/TeachController.php)

class TeachController extends Controller
{
    public function get_teach(Illuminate\Http\Request $request)
    {
        $teach_id = $request->get('teach_id');          
        $teachers=\App\Teacher::where('teacher_id','=',$dept_id)->get();
        return response()->json(['response' => $teachers]);
    }
}

那么在你的 AJAX 脚本中你至少可以使用以下方式之一

1. 在 javascript 代码中使用绝对网址

   var base_url = 'http://localhost/laravel'
   $.ajax({
          type: "GET",
          url : base_url+"/ajaxteach",
          data : dataString,
          success : function(data){
                 console.log(data);
          }
   

2. 在路由中使用url()

   $.ajax({
          type: "POST",
          url : "{{url('ajaxteach')}}",
          data : dataString,
          success : function(data){
                 console.log(data);
          }