如何删除重复的 Json 信息？答案

【问题标题】：How to remove repeat Json information?如何删除重复的 Json 信息？
【发布时间】：2015-10-02 13:13:06
【问题描述】：

数据库：

`--> product table
id  name      cid     uploadKey
1   Cemera     1       7365
2   Notebook   2       7222`

`--> category table
id    catename
1      canon
2      toshiba`


`--> attactments table
id      uploadKey       filepath
1       7365            /img/jdf.png
2       7365            /img/sdsd.jpg`

创建json文件的代码：

$_GET['id']="1";
 $json_response = array();
    if(isset($_GET['id']))
    {
        $id=$_GET['id'];        
 $select = mysql_query("SELECT product.name,category.catename,attactments.filepath FROM product INNER JOIN category ON category.id = product.cid INNER JOIN attactments ON attactments.uploadKey = product.uploadKey where product.id='".$id."'  ");
    while ($row = mysql_fetch_array($select , MYSQL_ASSOC)) {       
        $json_response[] = $row;
         } 
    }
 echo $val= str_replace('\\/', '/', json_encode($json_response));

结果重复信息，如何删除重复我想显示如下：

[{"name":"Cemera","catename":"canon","filepath":"/img/jdf.png"},{"name":"Cemera","catename":"canon","filepath":"/img/sdsd.jpg"}]

我想这样展示，我们如何编辑它：

[{"name":"Cemera","catename":"canon","filepath":"/img/jdf.png","filepath":"/img/sdsd.jpg"}]

【问题讨论】：

这会帮助你stackoverflow.com/questions/23507853/…stackoverflow.com/questions/18034696/…

标签： php jquery mysql arrays json

【解决方案1】：

Put limit 0,1 at the end of query.
$select = mysql_query("SELECTproduct.name,category.catename,attactments.filepath FROM product INNER JOIN category ON category.id = product.cid INNER JOIN attactments ON attactments.uploadKey = product.uploadKey where product.id='".$id."' lomit 0,1 ");

我认为它有帮助..

【讨论】：

【解决方案2】：

你可以GROUP_CONCAT()文件路径，试试下面的代码

$select = mysql_query("SELECT product.name,category.catename,GROUP_CONCAT(attactments.filepath SEPARATOR ',') AS filepath FROM product INNER JOIN category ON category.id = product.cid INNER JOIN attactments ON attactments.uploadKey = product.uploadKey where product.id='".$id."'  ");

while ($row = mysql_fetch_array($select , MYSQL_ASSOC)) {   
   $row['filepath'] = explode(',',$row['filepath']);
        $json_response[] = $row;
         }

然后你会得到以下结果

{"name":"Cemera","catename":"canon","filepath":["\/img\/jdf.png","\/img\/sdsd.jpg"]}

【讨论】：

谢谢你的回答，能不能这样给我[{"name":"Cemera","catename":"canon","filepath":"/img/jdf.png" ,"文件路径":"/img/sdsd.jpg"}]
您希望如何在同一个键中赋予不同的值？有可能吗？

【解决方案3】：

所有文件路径都应使用 GROUP_CONCAT 以逗号分隔。像这样

$select = mysql_query("SELECT product.name,category.catename,attactments.filepath 
FROM product 
INNER JOIN category ON category.id = product.cid 
INNER JOIN(SELECT uploadKey, GROUP_CONCAT(filepath SEPARATOR ',') FROM attactments GROUP BY uploadKey) a ON a.uploadKey = product.uploadKey where product.id='".$id."'  ");

【讨论】：