【发布时间】:2020-06-20 17:54:32
【问题描述】:
我尝试实现我自己的表达式序列化器/反序列化器以通过服务传递它(我想实现我自己的 EF Core 服务端点)。 所以,现在我对 LambdaExpressions 中的集合有疑问。例如,
var dataQuery = testDb.Users.Include(e => e.EmployeeInfo).Include(f => f.Notifications).Where(s => tstList.Contains(s.Id)).Select(e => e.FullName);
var tstEspressionBase = dataQuery.Expression;
var tstEspression = new ReflectionLocalValculationVisitor().Visit(tstEspressionBase);
这里
public class ReflectionLocalValculationVisitor : ExpressionVisitor
{
protected override Expression VisitMember(MemberExpression memberExpression)
{
var expression = Visit(memberExpression.Expression);
if (expression is ConstantExpression)
{
object container = ((ConstantExpression)expression).Value;
var member = memberExpression.Member;
if (member is FieldInfo)
{
object value = ((FieldInfo)member).GetValue(container);
return Expression.Constant(value);
}
if (member is PropertyInfo)
{
object value = ((PropertyInfo)member).GetValue(container, null);
return Expression.Constant(value);
}
}
return base.VisitMember(memberExpression);
}
}
var tstList = new List<Guid>()
{
new Guid("D45E1A1A-F546-48DB-77BA-08D7775C6A93"),
new Guid("5B21C782-9B95-48F2-77BD-08D7775C6A93")
};
使用此代码执行
var providerAsync = testDb.GetService<IAsyncQueryProvider>();
var toListAsyncMethodInfo = typeof(EntityFrameworkQueryableExtensions).GetMethod(nameof(EntityFrameworkQueryableExtensions.ToListAsync)).MakeGenericMethod(typeof(string));
var s3 = await toListAsyncMethodInfo.InvokeAsync(null, new object[] { providerAsync.CreateQuery(tstEspression), default(CancellationToken) }).ConfigureAwait(false);
给我正确的结果。
因此,在使用 Newtonsoft Json 进行序列化/反序列化后,我在 Lambda from Where 方法中的收集出现问题:
错误消息:LINQ 表达式 'DbSet .Where(u => List { d45e1a1a-f546-48db-77ba-08d7775c6a93, 5b21c782-9b95-48f2-77bd-08d7775c6a93, }.Contains(s.Id))' 不能 翻译。要么以可翻译的形式重写查询, 或通过插入调用显式切换到客户端评估 AsEnumerable()、AsAsyncEnumerable()、ToList() 或 ToListAsync()。见https://go.microsoft.com/fwlink/?linkid=2101038 更多信息。
我试图实现这个“建议”,但没有效果(见下面的代码):
var asEnumerableMethod = typeof(Enumerable).GetMethod(nameof(Enumerable.AsEnumerable)).MakeGenericMethod(GenericTypes.Select(e => e.FromNode()).ToArray());
var asEnumerabled = asEnumerableMethod.Invoke(null, new object[] { Value });
这里的Value对象是JSON.NET反序列化后生成的List<Guid>。
所以,我比较了ConstantExpression 中Value 实现的接口,它代表List<guid> 在序列化之前和反序列化之后——都实现了8 个接口。
所以,也许有人遇到了同样的问题。
谢谢。
附:我不知道为什么 EF Core 给我Where(u => ... 而不是Where(s => ...,因为在此表达式的 DebugView 模式下,我看到了正确的Where(s => ... 表示。
让我们看看序列化/(反序列化和恢复的)表达式(来自 DebugView 的数据):
.Call System.Linq.Queryable.Select(
.Call System.Linq.Queryable.Where(
.Call Microsoft.EntityFrameworkCore.EntityFrameworkQueryableExtensions.Include(
.Call Microsoft.EntityFrameworkCore.EntityFrameworkQueryableExtensions.Include(
.Constant<Microsoft.EntityFrameworkCore.Query.Internal.EntityQueryable`1[EFCoreDataModel.DataClasses.Users.Base.User]>(Microsoft.EntityFrameworkCore.Query.Internal.EntityQueryable`1[EFCoreDataModel.DataClasses.Users.Base.User]),
'(.Lambda #Lambda1<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,EFCoreDataModel.DataClasses.Users.Employ.EmployeeInfo]>))
,
'(.Lambda #Lambda2<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Collections.Generic.ICollection`1[EFCoreDataModel.DataClasses.Notifications.Notification]]>))
,
'(.Lambda #Lambda3<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Boolean]>)),
'(.Lambda #Lambda4<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.String]>))
.Lambda #Lambda1<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,EFCoreDataModel.DataClasses.Users.Employ.EmployeeInfo]>(EFCoreDataModel.DataClasses.Users.Base.User $e)
{
$e.EmployeeInfo
}
.Lambda #Lambda2<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Collections.Generic.ICollection`1[EFCoreDataModel.DataClasses.Notifications.Notification]]>(EFCoreDataModel.DataClasses.Users.Base.User $f)
{
$f.Notifications
}
.Lambda #Lambda3<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Boolean]>(EFCoreDataModel.DataClasses.Users.Base.User $s)
{
.Call .Constant<System.Collections.Generic.List`1[System.Guid]>(System.Collections.Generic.List`1[System.Guid]).Contains($s.Id)
}
.Lambda #Lambda4<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.String]>(EFCoreDataModel.DataClasses.Users.Base.User $e)
{
$e.FullName
}
原始表达式(来自 DebugView):
.Call System.Linq.Queryable.Select(
.Call System.Linq.Queryable.Where(
.Call Microsoft.EntityFrameworkCore.EntityFrameworkQueryableExtensions.Include(
.Call Microsoft.EntityFrameworkCore.EntityFrameworkQueryableExtensions.Include(
.Constant<Microsoft.EntityFrameworkCore.Query.Internal.EntityQueryable`1[EFCoreDataModel.DataClasses.Users.Base.User]>(Microsoft.EntityFrameworkCore.Query.Internal.EntityQueryable`1[EFCoreDataModel.DataClasses.Users.Base.User]),
'(.Lambda #Lambda1<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,EFCoreDataModel.DataClasses.Users.Employ.EmployeeInfo]>))
,
'(.Lambda #Lambda2<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Collections.Generic.ICollection`1[EFCoreDataModel.DataClasses.Notifications.Notification]]>))
,
'(.Lambda #Lambda3<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Boolean]>)),
'(.Lambda #Lambda4<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.String]>))
.Lambda #Lambda1<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,EFCoreDataModel.DataClasses.Users.Employ.EmployeeInfo]>(EFCoreDataModel.DataClasses.Users.Base.User $e)
{
$e.EmployeeInfo
}
.Lambda #Lambda2<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Collections.Generic.ICollection`1[EFCoreDataModel.DataClasses.Notifications.Notification]]>(EFCoreDataModel.DataClasses.Users.Base.User $f)
{
$f.Notifications
}
.Lambda #Lambda3<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.Boolean]>(EFCoreDataModel.DataClasses.Users.Base.User $s)
{
.Call .Constant<System.Collections.Generic.List`1[System.Guid]>(System.Collections.Generic.List`1[System.Guid]).Contains($s.Id)
}
.Lambda #Lambda4<System.Func`2[EFCoreDataModel.DataClasses.Users.Base.User,System.String]>(EFCoreDataModel.DataClasses.Users.Base.User $e)
{
$e.FullName
}
所以,他们是平等的。并且序列化/反序列化在 Lambda 中没有 u 参数,只是 's'。
【问题讨论】:
标签: c# linq .net-core entity-framework-core expression-trees