【发布时间】:2011-11-02 09:01:17
【问题描述】:
我是 MPI 的初学者,我想通过以下方式在 MPI 中使用线程。某些进程(甚至所有进程)会产生线程并进行阻塞等待以接收消息。每个 proc 产生的线程数是一个命令行参数。因此,如果有 4 个 proc,则进程 0 和 2 会产生一个线程。现在,我希望进程 0 和 2 都向所有线程发送消息。例如,进程 0 向自身 AND 向进程 2 发送消息,而 proc 2 将消息发送给 proc 0 和自身。 这是我的代码的样子,它显然没有达到预期的效果。它只是等待接收消息。我哪里错了?
谢谢!
typedef struct {
int id;
} struct_t;
void *hello(void *arg)
{
int rank;
char mystr[10];
MPI_Status status;
struct_t *fd=(struct_t *)arg;
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
printf("Rank %d is waiting in thread %d for my message\n", rank, fd->id);
if(rank%2 ==0){
MPI_Recv(mystr, 10, MPI_CHAR, MPI_ANY_SOURCE, 0, MPI_COMM_WORLD, &status);
printf("Thread %d on rank %d received %s\n", fd->id, rank, mystr);
}
return (NULL);
}
void spawn_thread(int n)
{
int size,rank, i;
pthread_t *threads;
pthread_attr_t pthread_custom_attr;
struct_t *fd;
threads=(pthread_t *)malloc(n*sizeof(*threads));
pthread_attr_init(&pthread_custom_attr);
fd=(struct_t *)malloc(sizeof(struct_t)*n);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &size);
/* Start up thread */
for (i=0; i<n; i++)
{
fd[i].id=i;
// printf("My rank is %d and I created thread #%d\n", rank, i);
pthread_create(&threads[i], &pthread_custom_attr, hello, (void *)(fd+i));
}
/* Synchronize the completion of each thread. */
for (i=0; i<n; i++)
{
pthread_join(threads[i],NULL);
}
free(fd);
}
void main(int argc, char ** argv)
{
int n,i, provided, claimed;
int rank, size, errs;
MPI_Init_thread(&argc, &argv, MPI_THREAD_MULTIPLE, &provided);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &size);
if (argc != 2)
{
printf ("Usage: %s n\n where n is no. of threads\n",argv[0]);
exit(1);
}
n=atoi(argv[1]);
if ((n < 1) || (n > MAX_THREAD))
{
printf ("The no of thread should between 1 and %d.\n",MAX_THREAD);
MPI_Abort(MPI_COMM_WORLD,-1);
}
if(rank%2 == 0)
spawn_thread(n);
if(rank%2 == 0){
printf("My rank is %d and I am sending Hello!\n", rank);
MPI_Send("HELLOOO", 10, MPI_CHAR, rank, 0, MPI_COMM_WORLD);
}
MPI_Finalize();
}
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