【发布时间】:2017-11-22 04:57:44
【问题描述】:
我有一个二维整数数组,我想将它的行发送到每个单独的进程。我假设行数(M = 5)不能被进程数(大小 = 4)整除,所以在我的情况下,进程 0 将获得额外的行。二维数组 A 的大小为 MxN (5x10)。
这是我的代码
PROGRAM SCATTERV_MATRIX
INCLUDE 'mpif.h'
integer :: rank, size, ierr, dest, src, tag !MPI variables
integer :: status(MPI_STATUS_SIZE) !MPI variables
INTEGER, PARAMETER :: N = 10 !number of columns
INTEGER, PARAMETER :: M = 5 !number of rows
INTEGER, ALLOCATABLE, DIMENSION(:,:) :: A !MxN matrix A
INTEGER :: NEWTYPE, RESIZEDTYPE !MPI derived data types
INTEGER, ALLOCATABLE, DIMENSION(:,:) :: LOCAL
INTEGER, ALLOCATABLE :: SENDCOUNTS(:), DISPLS(:)
INTEGER :: RECVCOUNT, NRBUF
INTEGER :: MMIN, MEXTRA, INTSIZE, K, I, J
INTEGER :: START, EXTENT !(KIND=MPI_ADRESS_KIND)
CALL MPI_INIT(ierr)
CALL MPI_COMM_RANK(MPI_COMM_WORLD, rank, ierr)
CALL MPI_COMM_SIZE(MPI_COMM_WORLD, size, ierr)
IF ( rank == 0 ) THEN !allocate and create 2Darray
ALLOCATE( A (M, N) )
K = 1
DO I = 1, M
DO J = 1, N
A(I, J) = K
K = K + 1
END DO
END DO
END IF
ALLOCATE( SENDCOUNTS(0:size-1), DISPLS(0:size-1) )
MMIN = M/size !number of rows divided by number of processors
MEXTRA = MOD(M, size) !extra rows
K = 0
DO I = 0, size-1
IF (I < MEXTRA) THEN !SENDCOUNTS=(/2,1,1,1/)
SENDCOUNTS(I) = MMIN + 1
ELSE
SENDCOUNTS(I) = MMIN
END IF
DISPLS(I) = K !DISPLS=(/0,2,3,4/)
K = K + SENDCOUNTS(I)
END DO
RECVCOUNT = SENDCOUNTS(rank)
ALLOCATE( LOCAL(RECVCOUNT,N) )
CALL MPI_TYPE_VECTOR(N, 1, M, MPI_INTEGER, NEWTYPE, ierr)
CALL MPI_TYPE_COMMIT(NEWTYPE, ierr)
START = 0
CALL MPI_TYPE_SIZE(MPI_INTEGER, INTSIZE, ierr)
EXTENT = 1*INTSIZE
CALL MPI_TYPE_CREATE_RESIZED(NEWTYPE, START, EXTENT, RESIZEDTYPE, ierr)
CALL MPI_TYPE_COMMIT(RESIZEDTYPE, ierr)
LOCAL(:, :) = 0
CALL MPI_SCATTERV( &
A, SENDCOUNTS, DISPLS, RESIZEDTYPE, &
LOCAL, RECVCOUNT*N, MPI_INTEGER, &
0, MPI_COMM_WORLD, ierr)
WRITE(*,*) rank, ':', LOCAL
CALL MPI_FINALIZE(ierr)
END PROGRAM SCATTERV_MATRIX
成功编译后,出现“程序异常 - 访问冲突”错误。我以前的所有 Fortan MPI 程序都运行良好。代码中一定有一些错误,可能在 MPI_SCATTERV 中。 我主要关注这个answer。我将不胜感激任何建议。谢谢。
【问题讨论】:
-
如果你使用
use mpi而不是include mpif.h,编译器可以做更多的检查并且发现sidentify几种错误