【发布时间】:2020-11-30 16:10:46
【问题描述】:
我正在尝试首先使用 asp.net core 3.1 代码实现级联下拉列表。我有两张表,分别是车辆制造商和车辆型号。第一个下拉列表将填充品牌,并在选择任何品牌时,第二个下拉列表将填充模型。但我在模型下拉列表中一直未定义。下面是我的实现。请问我做错了什么?谢谢
IVehicleService 接口
namespace Application.Common.Interfaces
{
public interface IVehicleService
{
IEnumerable<VehicleMake> GetMakes();
IEnumerable<VehicleModel> GetModels(int categoryId);
}
}
车辆服务
namespace Application.Common.Interfaces
{
public class VehcicleService : IVehicleService
{
private readonly IApplicationDbContext _dbContext;
public VehcicleService(IApplicationDbContext dbContext)
{
_dbContext = dbContext;
}
public IEnumerable<VehicleMake> GetMakes()
{
IEnumerable<VehicleMake> makes = _dbContext.VehicleMakes.ToList();
return makes;
}
public IEnumerable<VehicleModel> GetModels(int MakeId)
{
IEnumerable<VehicleModel> model = _dbContext.VehicleModels.Where(x => x.VehicleMakeId == MakeId).ToList();
return model;
}
}
}
我的模特页面
namespace Wbc.WebUI.Areas.Tools.Pages
{
public class SearchByMakeModel : PageModel
{
private readonly IVehicleService _vehicleService;
public SearchByMakeModel(IVehicleService vehicleService)
{
_vehicleService = vehicleService;
}
[BindProperty(SupportsGet = true)]
public int MakeId { get; set; }
public int ModelId { get; set; }
public SelectList MakeListdll { get; set; }
public void OnGet()
{
MakeListdll = new SelectList(_vehicleService.GetMakes(), nameof(VehicleMake.Id),
nameof(VehicleMake.Name));
}
public JsonResult OnGetSubCategories()
{
return new JsonResult(_vehicleService.GetModels(MakeId));
}
}
}
我的剃刀标记
<select asp-for="MakeId" asp-items="Model.MakeListdll">
<option value=""></option>
</select>
<select asp-for="ModelId">
</select>
接口及其实现在Startup中注册到依赖注入系统:
services.AddTransient<IVehicleService, VehcicleService>();
我的 Ayax 电话
@section scripts{
<script type="text/javascript">
$(function () {
$("#MakeId").on("change", function() {
var makeId = $(this).val();
$("#ModelId").empty();
$("#ModelId").append("<option value=''>Select Model</option>");
$.getJSON(`?handler=OnGetModels&MakeId=${makeId}`, (data) => {
$.each(data, function (i, item) {
$("#ModelId").append(`<option value="${item.Id}">${item.Name}</option>`);
});
});
});
});
</script>
}
【问题讨论】:
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