如何在 Android 中获取网关和子网掩码详细信息？
【问题讨论】：
标签： android networking ip-address
此版本适用于任何网络（Wifi/Cell）。返回 V4 和 V6。
/**
* Returns the set of all gateways<V4 & V6> for any Network
*
*/
fun getGatewaySet(network:Network, context:Context):MutableSet<InetAddress> {
val connectivityManager = context.getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager
connectivityManager.getLinkProperties(network)?.routes?.let {
//Saw dupes on my device, so use a set
val set = mutableSetOf<InetAddress>()
for (routeInfo in it) {
routeInfo?.gateway?.let { inetAddress ->
//If comes from AOSP isGateway() - requires API 29
if (!inetAddress.isAnyLocalAddress) {
set.add(inetAddress)
}
}
}
return set
}
return Collections.EMPTY_SET as MutableSet<InetAddress>
}
【讨论】：
这是一个旧线程，但我找到了android API使用的官方函数（包android.net.NetworkUtils）：
/**
* Convert a IPv4 address from an integer to an InetAddress.
* @param hostAddress an int corresponding to the IPv4 address in network byte order
*/
public static InetAddress intToInetAddress(int hostAddress) {
byte[] addressBytes = { (byte)(0xff & hostAddress),
(byte)(0xff & (hostAddress >> 8)),
(byte)(0xff & (hostAddress >> 16)),
(byte)(0xff & (hostAddress >> 24)) };
try {
return InetAddress.getByAddress(addressBytes);
} catch (UnknownHostException e) {
throw new AssertionError();
}
}
一旦你有了InetAddress，你就可以通过这种方式获得格式化的字符串：
intToInetAddress(d.gateway).getHostAddress()
【讨论】：
虽然老了，但很有魅力。
tvGateway.setText(Formatter.formatIpAddress(dhcpInfo.gateway));
【讨论】：
而不是获得 255.255.255.0，只需更改顺序作为回报；）因此您将能够以正确的顺序获得...
public String intToIp(int i) {
return (i & 0xFF) + "." +
((i >> 8 ) & 0xFF) + "." +
((i >> 16 ) & 0xFF) + "." +
((i >> 24 ) & 0xFF) ;
}
【讨论】：
我在android.net 包中找到了一个名为DhcpInfo 的类。它有一些存储当前网络参数值的公共变量。但问题是它们返回从 8Bit 移位二进制转换而来的整数值。
描述场景的示例图片：
****这里是一个示例代码：**
**java 文件：****
package com.schogini.dhcp;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.widget.TextView;
import android.net.*;
import android.net.wifi.WifiManager;
public class dhcpInfo extends Activity {
public String s_dns1 ;
public String s_dns2;
public String s_gateway;
public String s_ipAddress;
public String s_leaseDuration;
public String s_netmask;
public String s_serverAddress;
TextView info;
DhcpInfo d;
WifiManager wifii;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
wifii= (WifiManager) getSystemService(Context.WIFI_SERVICE);
d=wifii.getDhcpInfo();
s_dns1="DNS 1: "+String.valueOf(d.dns1);
s_dns2="DNS 2: "+String.valueOf(d.dns2);
s_gateway="Default Gateway: "+String.valueOf(d.gateway);
s_ipAddress="IP Address: "+String.valueOf(d.ipAddress);
s_leaseDuration="Lease Time: "+String.valueOf(d.leaseDuration);
s_netmask="Subnet Mask: "+String.valueOf(d.netmask);
s_serverAddress="Server IP: "+String.valueOf(d.serverAddress);
//dispaly them
info= (TextView) findViewById(R.id.infolbl);
info.setText("Network Info\n"+s_dns1+"\n"+s_dns2+"\n"+s_gateway+"\n"+s_ipAddress+"\n"+s_leaseDuration+"\n"+s_netmask+"\n"+s_serverAddress);
}
}
xml编码：
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.schogini.dhcp"
android:versionCode="1"
android:versionName="1.0">
<uses-sdk android:minSdkVersion="4" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".dhcpInfo"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
</manifest>
我尝试将整数值转换为其等效值，但我做不到。如果你这样做，你可以回帖..再见..
更新：如何设法将 IP 从整数形式转换为 v4 格式 转换为 IPv4 格式：
public String intToIp(int i) {
return ((i >> 24 ) & 0xFF ) + "." +
((i >> 16 ) & 0xFF) + "." +
((i >> 8 ) & 0xFF) + "." +
( i & 0xFF) ;
}
Formatter.formatIpAddress(int) 已弃用，我们不想使用已弃用的方法吗？
AndroidKid 的这个版本在某种程度上被颠倒了，但这应该可以解决它：
public String intToIp(int addr) {
return ((addr & 0xFF) + "." +
((addr >>>= 8) & 0xFF) + "." +
((addr >>>= 8) & 0xFF) + "." +
((addr >>>= 8) & 0xFF));
}
来源：http://www.devdaily.com/java/jwarehouse/android/core/java/android/net/DhcpInfo.java.shtml
【讨论】：
使用Formatter.formatIpAddress(mask); 掩码是你的int。
String maskk = Formatter.formatIpAddress(mask);
【讨论】：
要格式化 ip，请尝试使用：
import android.text.format.Formatter;
public String FormatIP(int IpAddress)
{
return Formatter.formatIpAddress(IpAddress);
}
【讨论】：