【问题标题】:Creating Hyperlink between sheets where they all are in same workbook在它们都在同一个工作簿中的工作表之间创建超链接
【发布时间】:2017-06-14 00:30:57
【问题描述】:

下面的代码创建了一个超链接,但每当我单击该超链接时,它都会显示“无法打开指定的文件”。

from openpyxl import load_workbook
s1 = "C:/santosh_chikne/python/Excel/test1.xlsx"

wb = load_workbook(s1)

ws = wb.get_sheet_by_name("Index")

a="A"

b="B"

rownums=4

col=2

sheetname=wb.get_sheet_names()

for i in sheetname:

    link = str(s1)+"#"+str(i)+"A1"

    url2 = str(i)

    ws.cell(row=rownums, column=col).hyperlink=link

    rownums=rownums+1

wb.save(s1)

【问题讨论】:

    标签: python excel python-2.7 hyperlink


    【解决方案1】:

    我无法测试这个,因为我的办公机器上没有安装 Python,但我认为这样的东西应该可以为你完成这项工作。

    import xlsxwriter
    
    # Create a new workbook and add a worksheet
    workbook = xlsxwriter.Workbook('hyperlink.xlsx')
    worksheet = workbook.add_worksheet('Hyperlinks')
    
    # Format the first column
    worksheet.set_column('A:A', 30)
    
    # Add the standard url link format.
    url_format = workbook.add_format({
        'font_color': 'blue',
        'underline':  1
    })
    
    # Add a sample alternative link format.
    red_format = workbook.add_format({
        'font_color': 'red',
        'bold':       1,
        'underline':  1,
        'font_size':  12,
    })
    
    # Add an alternate description string to the URL.
    string = 'Python home'
    
    # Add a "tool tip" to the URL.
    tip = 'Get the latest Python news here.'
    
    # Write some hyperlinks
    worksheet.write_url('A1', 'http://www.python.org/')  # Implicit format.
    worksheet.write_url('A3', 'http://www.python.org/', url_format, string)
    worksheet.write_url('A5', 'http://www.python.org/', url_format, string, tip)
    worksheet.write_url('A7', 'http://www.python.org/', red_format)
    worksheet.write_url('A9', 'mailto:jmcnamara@cpan.org', url_format, 'Mail me')
    
    # Write a URL that isn't a hyperlink
    worksheet.write_string('A11', 'http://www.python.org/')
    
    workbook.close()
    

    或者,这个。

    from openpyxl import load_workbook
    
    wb = load_workbook(workbookEx.xlsx) 
    ws = wb.get_sheet_by_name("sheet1")
    
    link = "workbookEx.xlsx#sheet2!E5"
    
    ws.cell(row=1, column=1).hyperlink = (link)
    

    【讨论】:

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