【发布时间】:2021-03-10 09:16:00
【问题描述】:
我在 MySQL 上编写代码,但它给了我错误。
这是我的代码,它给了我错误 - “错误代码:1826。重复的外键约束名称'menu_ibfk_1'”
当我给出不同的约束名称时,它给了我错误 - “错误代码:1822。无法添加外键约束。在引用的表 'menu' 中缺少约束 'menu_ibfk_2' 的索引”
create database WasteManagement;
CREATE TABLE WasteManagement.Faculty_login (
Faculty_ID int(9) NOT NULL ,
FName varchar(50) DEFAULT NULL,
Department varchar(20) DEFAULT NULL,
Password varchar(20) DEFAULT NULL,
PRIMARY KEY (Faculty_ID) );
CREATE TABLE WasteManagement.Student_login (
Enrollment_No int(11) NOT NULL ,
SName varchar(50) DEFAULT NULL,
Course varchar(20) DEFAULT NULL,
Password varchar(20) DEFAULT NULL,
PRIMARY KEY (Enrollment_No) );
CREATE TABLE WasteManagement.Staff_login (
Staff_ID int(9) NOT NULL ,
CName varchar(50) DEFAULT NULL,
Username varchar(20) DEFAULT NULL,
Password varchar(20) DEFAULT NULL,
PRIMARY KEY (Staff_ID) );
CREATE TABLE WasteManagement.Menu (
Staff_ID int(9) NOT NULL,
Datee date NOT NULL DEFAULT 0,
Timee varchar(10) NOT NULL,
Dish varchar(30) NOT NULL,
PRIMARY KEY (Datee, Timee, Dish)
#FOREIGN KEY (Staff_ID) References Menu(Staff_ID)
);
CREATE TABLE WasteManagement.Demand1 (
Datee date NOT NULL DEFAULT 0,
Timee varchar(10) NOT NULL,
Dish varchar(30) NOT NULL,
S_demand BOOLEAN DEFAULT FALSE,
PRIMARY KEY (Datee, Timee, Dish, S_demand),
KEY d1 (datee),
KEY t1 (Timee),
KEY dish1 (Dish),
#KEY `AuthorID` (`AuthorID`),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Datee) References Menu(Datee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Timee) References Menu(Timee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Dish) References Menu(Dish));
CREATE TABLE WasteManagement.Demand2 (
Datee date NOT NULL DEFAULT 0,
Timee varchar(10) NOT NULL,
Dish varchar(30) NOT NULL,
F_demand BOOLEAN NOT NULL DEFAULT FALSE,
PRIMARY KEY (Datee, Timee, Dish, F_demand),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Datee) References Menu(Datee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Timee) References Menu(Timee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Dish) References Menu(Dish));
CREATE TABLE WasteManagement.Feedback1 (
Datee date NOT NULL DEFAULT 0,
Timee varchar(10) NOT NULL,
Dish varchar(30) NOT NULL,
eaten_by1 int(7) NOT NULL,
s_rating int(1) NOT NULL,
PRIMARY KEY (Datee, Timee, Dish, eaten_by1, s_rating),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Datee) References Menu(Datee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Timee) References Menu(Timee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Dish) References Menu(Dish));
CREATE TABLE WasteManagement.Feedback2 (
Datee date NOT NULL DEFAULT 0,
Timee varchar(10) NOT NULL,
Dish varchar(30) NOT NULL,
eaten_by2 int(7) NOT NULL,
f_rating int(1) NOT NULL,
PRIMARY KEY (Datee, Timee, Dish, eaten_by2, f_rating),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Datee) References Menu(Datee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Timee) References Menu(Timee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Dish) References Menu (Dish));
CREATE TABLE WasteManagement.Wastage (
Datee date NOT NULL DEFAULT 0,
Timee varchar(10) NOT NULL,
Dish varchar(30) NOT NULL,
Produced_qty int(7) NOT NULL,
Wasted_qty int(7) NOT NULL,
PRIMARY KEY (Datee, Time, Dish, Produced_qty, Wasted_qty),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Datee) References Menu(Datee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Timee) References Menu(Timee),
CONSTRAINT `menu_ibfk_1` FOREIGN KEY (Dish) References Menu(Dish));
这是 MySQL 输出的快照
我做错了什么?
【问题讨论】:
-
当然,您可以将示例简化为两个或三个表。
-
要么跳过约束名称,要么为每个外键设置唯一的名称。
-
它仍然给出没有约束名称的错误 - 错误代码:1822。无法添加外键约束。引用表 'menu' 中的约束 'demand1_ibfk_2' 缺少索引
-
这是另一个问题。正如 Gordon 所说,尽量减少问题 - minimal reproducible example。助您轻松!
-
如果我没记错的话,mysql 不允许多个外键同名。至于您的第二个错误,您的
Menu表的 DDL(创建语句)是什么?
标签: mysql sql compiler-errors runtime-error error-code