在MYSQL中创建表时的数据转换

Question

创建表时出错，但 SQL 正在检索结果

请找到下面的代码，下面的 SQL 本身就可以很好地检索结果！

SELECT 
CASE WHEN J.JOBID = DJ.JOBNUMBER
     THEN DJ.JOBID ELSE J.JOBID 
                 END AS JOBID, 
J.DISTRICTID,   
CASE WHEN D.DISTRICTID = J.DISTRICTID 
     THEN D.NAME ELSE NULL 
                 END AS DISTRICT_NAME,
D.SEGMENTID,
CASE WHEN D.SEGMENTID = S.SEGMENTID AND D.DISTRICTID = J.DISTRICTID
     THEN S.NAME ELSE NULL 
                 END AS SEGMENT,
J.STARTTIME, 
J.ENDTIME, 
SJ.COMCATJOBTYPEID, 
J.JOBTYPEID,
CASE WHEN J.JOBTYPEID = JT.JOBTYPEID 
     THEN JT.NAME ELSE NULL 
                 END AS JOBTYPENAME,
TS.SSSEGMENT AS SUBPL_NAME,
CONCAT(D.DISTRICTID,TS.SSSEGMENT) AS DISTRICTSUBPLID
FROM `EAR-AA-242`.JOB J
LEFT JOIN `EAR-AA-242`.DISTRICT D ON J.DISTRICTID = D.DISTRICTID
LEFT JOIN `EAR-AA-242`.DMJOB DJ ON DJ.JOBNUMBER = J.JOBID 
LEFT JOIN `EAR-AA-242`.JOBTYPE JT ON JT.JOBTYPEID = J.JOBTYPEID
LEFT JOIN `EAR-AA-242`.STANDARDJOBTYPE SJ ON JT.STANDARDJOBTYPEID = SJ.STANDARDJOBTYPEID
LEFT JOIN `EAR-AA-239`.TBLJOBTYPE TJ ON SJ.COMCATJOBTYPEID = TJ.JOBTYPEID
LEFT JOIN (SELECT SS.SSSEGMENT, SS.NODEID FROM `EAR-AA-239`.TBLSSSEGMENT S, 
                    `EAR-AA-239`.TBLSSSEGMENT SS WHERE S.SSS = SS.PARENTSSS AND SS.DELETED = 0) TS ON TJ.SSSEGMENT =TS.NODEID                    
LEFT JOIN `EAR-AA-242`.SEGMENT S ON S.SEGMENTID = D.SEGMENTID
WHERE DATE(J.STARTTIME) > DATE_SUB(DATE(SYSDATE()), INTERVAL 367 DAY) 
ORDER BY J.JOBID;

相同的代码代码，在创建表时抛出一个 错误代码：1292。截断不正确的 DOUBLE 值：'11COC0011'

CREATE TABLE ODS.JOB_LOCATION_IDISTRICT AS

SELECT 
CASE WHEN J.JOBID = DJ.JOBNUMBER
     THEN DJ.JOBID ELSE J.JOBID 
                 END AS JOBID, 
J.DISTRICTID,   
CASE WHEN D.DISTRICTID = J.DISTRICTID 
     THEN D.NAME ELSE NULL 
                 END AS DISTRICT_NAME,
D.SEGMENTID,
CASE WHEN D.SEGMENTID = S.SEGMENTID AND D.DISTRICTID = J.DISTRICTID
     THEN S.NAME ELSE NULL 
                 END AS SEGMENT,
J.STARTTIME, 
J.ENDTIME, 
SJ.COMCATJOBTYPEID, 
J.JOBTYPEID,
CASE WHEN J.JOBTYPEID = JT.JOBTYPEID 
     THEN JT.NAME ELSE NULL 
                 END AS JOBTYPENAME,
TS.SSSEGMENT AS SUBPL_NAME,
CONCAT(D.DISTRICTID,TS.SSSEGMENT) AS DISTRICTSUBPLID
FROM `EAR-AA-242`.JOB J
LEFT JOIN `EAR-AA-242`.DISTRICT D ON J.DISTRICTID = D.DISTRICTID
LEFT JOIN `EAR-AA-242`.DMJOB DJ ON DJ.JOBNUMBER = J.JOBID 
LEFT JOIN `EAR-AA-242`.JOBTYPE JT ON JT.JOBTYPEID = J.JOBTYPEID
LEFT JOIN `EAR-AA-242`.STANDARDJOBTYPE SJ ON JT.STANDARDJOBTYPEID = SJ.STANDARDJOBTYPEID
LEFT JOIN `EAR-AA-239`.TBLJOBTYPE TJ ON SJ.COMCATJOBTYPEID = TJ.JOBTYPEID
LEFT JOIN (SELECT SS.SSSEGMENT, SS.NODEID FROM `EAR-AA-239`.TBLSSSEGMENT S, 
                    `EAR-AA-239`.TBLSSSEGMENT SS WHERE S.SSS = SS.PARENTSSS AND SS.DELETED = 0) TS ON TJ.SSSEGMENT =TS.NODEID                    
LEFT JOIN `EAR-AA-242`.SEGMENT S ON S.SEGMENTID = D.SEGMENTID
WHERE DATE(J.STARTTIME) > DATE_SUB(DATE(SYSDATE()), INTERVAL 367 DAY) 
ORDER BY J.JOBID;

非常感谢任何帮助！！！

Answer 1

您应该明确指定列的数据类型。没有它，MySQL 必须弄清楚类型是什么。当您使用CASE 表达式返回列的值时，它假定列数据类型将与第一个THEN 值的类型相同，但如果其他情况返回不同的值，这将是错误的类型。在您的代码中，您有一些 CASE 表达式，其中第一个结果是 DOUBLE，但另一个结果是无法转换为 DOUBLE 的 CHAR 字符串。

应该是这样的

CREATE TABLE ODS.JOB_LOCATION_IDISTRICT (
    JOBID VARCHAR(30),
    DISTRICTID INT,
    ...
) AS
SELECT 
...