【发布时间】:2021-10-16 03:17:45
【问题描述】:
我正在尝试创建一个脚本,该脚本对网站进行 API 调用以获取信息(通过请求模块)。 然后用户可以使用我的脚本/gui 来操作网站。
我的应用程序的主窗口底部有几个按钮,它们的作用类似于在窗口之间切换的选项卡(为了论证的缘故,假设有 2 个按钮在两个窗口之间切换)。
当进行某些更改时,我需要 QStackedWidget 来刷新当前未显示的某些窗口中的所有小部件/标签。
我的代码总结:
# Global Variables
app = QApplication(sys.argv)
win = QtWidgets.QStackedWidget()
response = {} # global dict to store API response from website
class UiWindowOne(QMainWindow):
# This window mostly shows information that I get from the website.
def __init__(self):
super(UiWindowOne, self).__init__()
self.setup_ui(self)
self.retranslate_ui(self)
# Then I map buttons to methods
def setup_ui(self, WindowOne):
# This was generated by QT Designer and places widgets
def retranslate_ui(self, WindowOne):
# This was generated by QT Designer and places widgets
def refresh(self):
'''
This function refreshes the current window. Basically, I put everything in the __init__ function in here (except "super(UiWindowOne, self).__init__()".
:return: None
'''
self.setup_ui(self)
self.retranslate_ui(self)
# Also map buttons to methods
class UiWindowTwo(QMainWindow):
def __init__(self):
super(UiWindowTwo, self).__init__()
self.setup_ui(self)
self.retranslate_ui(self)
# Then I map buttons to methods
def setup_ui(self, WindowTwo):
# This was generated by QT Designer
def retranslate_ui(self, WindowTwo):
# This was generated by QT Designer
def refresh(self):
'''
This function refreshes the current window. Basically, I put everything in the __init__ function in here (except "super(UiWindowTwo, self).__init__()".
:return: None
'''
self.setup_ui(self)
self.retranslate_ui(self)
# Also map buttons to methods
def update_website(self):
# Make changes to website
# After changes were made, I want to get modified info from the website and re-initialize/refresh both windows to reflect the changes made.
# I can easily call self.refresh() to refresh WindowTwo. But I cannot refresh WindowOne from here.
def main():
# Here I make API calls to the Website to get info/images
icon = QtGui.QIcon()
icon.addPixmap(QtGui.QPixmap(".\\imgs/static/A.png"), QtGui.QIcon.Mode.Normal, QtGui.QIcon.State.Off)
win.setWindowIcon(icon)
win.setWindowTitle("NAME")
first_window = UiWindowOne()
second_window = UiWindowTwo()
win.addWidget(first_window)
win.addWidget(second_window)
win.setGeometry(250, 250, 820, 854)
win.setFixedWidth(820)
win.setFixedHeight(854)
win.show()
sys.exit(app.exec())
if __name__ == '__main__':
main()
我曾尝试在 UiWindowTwo 的 update_website() 函数下执行“first_window.refresh()”,但随后 python 告诉我 first_window 未定义。
然后我尝试创建 first_window 和 second_window 全局变量,但后来我重新排序了整个脚本并且无法运行它。
【问题讨论】:
-
1.将
app和win的创建都移动到main,否则if __name__ == '__main__':将毫无意义,并且还会产生严重的问题; 2.不要将QMainWindows添加到QStackedWidget(我知道有教程这样做,但它们只是错误); 3. NOT 编辑 pyuic 生成的文件,也不要尝试将它们的内容与您的脚本合并;重新创建这些文件并学习如何正确 import 并按照有关 using Designer 的官方指南使用它们; 4.提供正确的minimal reproducible example
标签: python qt-designer qstackedwidget pyqt6