【发布时间】:2018-11-16 08:59:52
【问题描述】:
目前我正在尝试让 2 个按钮(几乎)同时运行。问题在于下面的代码,每个按钮都可以正常运行,但是当两个都被检查时,只有第一个运行。
import sys
from PyQt4.QtGui import *
from PyQt.QtCore import *
import os
import time
import traceback
class Worker(QRunnable):
def __init__(self, fn, *args, **kwargs):
super(Worker, self).__init__()
self.fn = fn
self.args = args
self.kwargs = kwargs
@pyqtSlot
def run(self):
try:
result = self.fn(*self.args, **self.kwargs)
except:
traceback.print_exc()
exctype, value = sys.exc_info()[:2]
self.signals.error.emit((exctype, value,
traceback.format_exc()))
else:
self.signals.result.emit(result)
finally:
self.signals.finished.emit()
class MainWindow(QMainWindow):
def __init__(self, *args, **kwargs):
super(MainWindow, self).__init__(*args, **kwargs)
layout = QVBoxLayout()
path = "Paths to watch"
path2 = "Paths to watch"
self.b = QPushButton("Button1")
self.b.setCheckable(True)
self.b.pressed.connect(lambda: self.watcher(path))
self.b2 = QPushButton("Button1")
self.b2.setCheckable(True)
self.b2.pressed.connect(lambda: self.watcher(path2))
layout.addWidget(self.b)
layout.addWidget(self.b2)
w = QWidget()
w.setLayout(layout)
self.setCentralWidget(w)
self.threadpool = QThreadPool()
def watcher(self, s):
worker = Worker(self.monitor(s))
self.threadpool.start(worker)
def monitor(self, s):
before = dict([(f, None) for f in os.listdir(s)])
while 1:
QCoreApplication.processEvents()
after = dict([(f, None) for f in os.listdir(s)])
added = [f for f in after if not f in before]
removed = [f for f in before if not f in after]
if added: print "Added: ", ", ".join(added)
if removed: print "Deleted: ", ", ".join(removed)
before = after
app = QApplication([])
window = MainWindow()
app.exec_()
不确定我是否需要分配线程,或者我是否可以通过某种方式让函数每 x 秒使用一个计时器更新 GUI ......或者如何实现它
【问题讨论】:
-
并行处理和多线程处理不同,都是2种并发,但又不一样,请记住。
-
你已经创建了那个代码?,你明白吗?
-
我猜只是错误的术语。这个想法是,当它们都被选中时,它至少会在两个按钮之间以一定的间隔反弹
-
我的问题是另一个,是你的代码还是你从其他地方得到的?我告诉你是因为我发现语法及其使用不一致。
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没问题,只是你必须把功劳归功于那些制作基本代码的人,另一方面它会帮助我理解你缺少你的代码,因为我看到你错过了一个很好的部分,我已经修补了你的代码,我也指出了错误,检查它:)
标签: python multithreading pyqt pyqt4