PySimpleGui - 获取按钮文本

Question

我正在使用 PySimpleGui 开发一个应用程序，它将从列表中分配按钮文本。用户搜索时，按钮上的文本会发生变化。我希望能够在按下按钮时阅读、打印和分配按钮文本。我怎么做？这是代码。我尝试了几件事无济于事。代码末尾的两条 print 语句是余数。

import PySimpleGUI as sg

selection_button_text_data = ['Like a Rolling Stone','Bob Dylan','The Sound of Silence','Simon & Garfunkel','Respect','Aretha Franklin','A Day In The Life','The Beatles']

layout =[
    [
        [sg.Button(selection_button_text_data[0])],
        [sg.Button(selection_button_text_data[1])],
        [sg.Button(selection_button_text_data[2])],
        [sg.Button(selection_button_text_data[3])]
    ]
        ]
window = sg.Window('Window Title', layout)
event, values = window.read()
window.close()
print(values)
print(sg.Button.GetText())

Answer 1

在您的情况下，最好为每个按钮提供每个键，然后您将获得与单击按钮的键相同的事件。通过window[key]可以获取元素并应用get_text()方法获取按钮文本。

import PySimpleGUI as sg

selection_button_text_data = [
    'Like a Rolling Stone',
    'Bob Dylan',
    'The Sound of Silence',
    'Simon & Garfunkel',
    'Respect',
    'Aretha Franklin',
    'A Day In The Life','The Beatles',
]

layout =[
    [sg.Button(selection_button_text_data[i], key=f'BTN{i}')] for i in range(4)
]
window = sg.Window('Window Title', layout)
event, values = window.read()
if event != sg.WINDOW_CLOSED:
    print(window[event].get_text())
window.close()

The Sound of Silence