【发布时间】:2015-10-31 06:48:13
【问题描述】:
我目前在pycharm中运行python程序有问题,我一般是右键运行程序。我想这样运行程序:
python hrllo.py rahulkapoo vit university
这是我得到的错误:
Traceback (most recent call last):
File "C:/Users/rahul/PycharmProjects/untitled/hrllo.py", line 107, in <module>
aggregate()
File "C:/Users/rahul/PycharmProjects/untitled/hrllo.py", line 88, in aggregate
br = login()
File "C:/Users/rahul/PycharmProjects/untitled/hrllo.py", line 23, in login
response = br.open('https://academics.vit.ac.in/student/stud_login.asp')
File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 203, in open
return self._mech_open(url, data, timeout=timeout)
File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 255, in _mech_open
raise response
mechanize._response.httperror_seek_wrapper: HTTP Error 403: request disallowed by robots.txt
Process finished with exit code 1
【问题讨论】:
-
您的预期结果是什么?你可以发布你的代码吗?你在说什么
python hrllo.py rahulkapoor vit university i don't know how to do this :?这是您在控制台或终端中输入的内容吗? -
在窗口的右上方选择您的脚本,然后点击编辑配置并在您的脚本出现的下方框中输入您的参数
标签: python python-2.7