【发布时间】：2014-01-19 16:53:44
【问题描述】：
代码：
#include <iostream>
void out()
{
}
template<typename T, typename... Args>
void out(T value, Args... args)
{
std::cout << value;
out(args...);
}
int main()
{
out("12345", " ", 5, "\n"); // OK
out(std::endl); // compilation error
return 0;
}
构建错误：
g++ -O0 -g3 -Wall -c -fmessage-length=0 -std=c++11 -pthread -MMD -MP -MF"main.d" -MT"main.d" -o "main.o" "../main.cpp"
../main.cpp: In function ‘int main()’:
../main.cpp:17:15: error: no matching function for call to ‘out(<unresolved overloaded function type>)’
../main.cpp:17:15: note: candidates are:
../main.cpp:3:6: note: void out()
../main.cpp:3:6: note: candidate expects 0 arguments, 1 provided
../main.cpp:8:6: note: template<class T, class ... Args> void out(T, Args ...)
../main.cpp:8:6: note: template argument deduction/substitution failed:
../main.cpp:17:15: note: couldn't deduce template parameter ‘T’
所以，除了std::endl，一切都很好。我该如何解决这个问题（使用“\n”除外）？
【问题讨论】：
-
out(&std::endl<char, std::char_traits<char>>);
标签： c++ c++11 variadic-templates