Youtube PHP APi 检查视频是否重复

Question

您好，我正在使用 Google PHP API 在 PHP 中上传视频。我已经按照this tutorial 实现了这一点，它工作正常。但是，如果我的频道中已经存在视频，则会出现问题，它还会返回视频详细信息，我找不到它因重复而被拒绝。

所以我找不到这是否是重复的视频，如果它是重复的，那么主视频是什么。表示被比较为重复的主视频的视频详细信息。

请帮我看看这是不是重复的视频？

Answer 1

我能想到的检查视频状态的唯一解决方案是使用表中的字段将视频标记为已处理或未处理。然后设置一个 cron 每小时运行一次（或者你想要的任何频率）来检查视频状态。

我的videos 表中的字段是processed。 NULL 表示未处理，0 表示已处理。 我的api 字段以 json 格式存储 YouTube 的视频 ID。

这是我的 cron 脚本：

# Starts the YouTubeService.
$youtube_obj=new Google_Service_YouTube($client);

# Get new uploaded videos from the database.
$unprocessed_videos=$db->get_results('SELECT `id`, `file_name`, `contributor`, `api` FROM `'.DBPREFIX.'videos` WHERE `processed` IS NULL');

# If there are new videos...
if($unprocessed_videos>0)
{
    # Loop through the new videos
    foreach($unprocessed_videos as $new_video)
    {
        # Has the video been processed? Default is TRUE. will be changed to FALSE if the video still has "uploaded" status.
        $video_processed=TRUE;

        # Decode the `api` field.
        $api_decoded=json_decode($new_video->api);
        # Get the YouTube Video ID.
        $video_yt_id=$api_decoded->youtube_id;

        if(isset($new_video->file_name))
        {
            # Set the path to the video on the server.
            $video_path='videos'.DS.$new_video->file_name;
        }

        $to='uploaders email';
        $reply_to='whomever';
        $subject="Video status from ".DOMAIN_NAME;
        $body='';

        # Check the video status.
        $check_status=$youtube_obj->videos->listVideos('status', array('id' => $video_yt_id));

        # Did YouTube return results?
        if(!empty($check_status['items']))
        {
            # Loop through the videos from YouTube.
            foreach($check_status['items'] as $status)
            {
                if($status['status']['uploadStatus']=="uploaded")
                {
                    # The video has not been processed yet so do not send an email.
                    $video_processed=FALSE;
                }
                # Check to see if the YouTube upload was a success.
                elseif($status['status']['uploadStatus']=="processed")
                {
                    # Tell the user the video was uploaded.
                    $body.='Your video has been uploaded to YouTube and can be viewed at http://'.FULL_DOMAIN.'media/videos/?video='.$new_video->id;
                }
                # Check if the uploaded video status is rejected.
                elseif($status['status']['uploadStatus']=="rejected")
                {
                    if(isset($new_video->file_name))
                    {
                        # Get the Upload class.
                        require_once 'Form'.DS.'Upload.php');
                        # Instantiate an Upload object.
                        $upload_obj=new Upload($video_path);
                        # Delete video file from server.
                        $upload_obj->deleteFile($video_path);

                        # Delete rejected video from YouTube
                        $delete_response=$youtube_obj->videos->delete($video_yt_id);
                    }

                    # Need to delete the entry from the database as well.
                    $db->query('DELETE FROM `'.DBPREFIX.'videos` WHERE `id` = '.$db->quote($new_video->id).' LIMIT 1');

                    # Check if the rejection status was a duplicate.
                    if($status['status']['rejectionReason']=="duplicate")
                    {
                        # Tell the user the video was a duplicate.
                        $body.='Your video was rejected because it was a duplicate video';
                    }
                }
            }
        }
        else
        {
            $body.='Your video was not found on YouTube';
            $video_processed=TRUE;
        }
        # Update database if the video has been "processed".
        if($video_processed===TRUE)
        {
            # Get the Email class.
            require_once 'Email'.DS.'Email.php');
            # Instantiate a new Email object.
            $mail_obj=new Email();
            $mail_obj->sendEmail($subject, $to, $body, $reply_to);
            # Set video to processed.
            $db->query('UPDATE `'.DBPREFIX.'videos` SET `processed` = 0 WHERE `id` = '.$db->quote($new_video->id).' LIMIT 1');
        }
    }
}

Answer 2

如果无法运行 cron 作业，您可能必须在下次尝试访问视频时检查它是否重复。

或者，在上传视频后，您可以启动另一个 php 脚本，该脚本会在一个 while 循环中定期检查状态（在发出另一个 API 请求检查之前休眠一段时间。）

do
{
    $videos = $youtubeClient->videos->listVideos('status', ['id' => $videoId]);
    $video = $videos['items'][0]; // assuming you want one video. Iterate over the items array otherwise

    if($video['status']['uploadStatus'] == 'rejected' && $video['status']['rejectionReason'] == 'duplicate') {
        // Notify user of duplicate and/or note failed upload in DB
    }
    else {
        sleep(180);
    }
} while ($video['status']['uploadStatus'] == 'processing')

您需要确保该脚本可以从命令行运行，并且可以接受参数以从原始上传脚本中获取视频 ID。 http://php.net/manual/en/function.getopt.php

我个人不喜欢使用这样的循环启动额外脚本的想法，因为如果您不检查所有边缘情况，您最终可能会出现 rouge 进程，但是如果没有 cron 作业，您的选择就会受到限制。