将列表作为参数传递给 Python C 模块？

Question

我找到了this Python C 模块的好例子，其中一个整数作为唯一的参数传递。我怎样才能将 python 列表作为参数传递？

Answer 1

来自http://code.activestate.com/lists/python-list/31841/：

...
char * tok;         /* delimiter tokens for strtok */
int cols;           /* number of cols to parse, from the left */

int numLines;       /* how many lines we passed for parsing */
char * line;        /* pointer to the line as a string */
char * token;       /* token parsed by strtok */

PyObject * listObj; /* the list of strings */
PyObject * strObj;  /* one string in the list */

/* the O! parses for a Python object (listObj) checked
   to be of type PyList_Type */
if (! PyArg_ParseTuple( args, "O!is", &PyList_Type, &listObj, 
           &cols, &tok )) return NULL;

/* get the number of lines passed to us */
numLines = PyList_Size(listObj);

/* should raise an error here. */
if (numLines < 0)   return NULL; /* Not a list */

...

/* iterate over items of the list, grabbing strings, and parsing
   for numbers */
for (i=0; i<numLines; i++){

/* grab the string object from the next element of the list */
strObj = PyList_GetItem(listObj, i); /* Can't fail */

/* make it a string */
line = PyString_AsString( strObj );

/* now do the parsing */

见Parsing arguments and building values

Answer 2

使用O arguments 和sequence protocol 之一。