【问题标题】:jQuery complex hide show submenujQuery 复杂的隐藏显示子菜单
【发布时间】:2018-03-25 05:36:46
【问题描述】:

我想不出一个合适的方法来完成所有需要的逻辑。出于布局目的,子菜单需要位于其菜单链接根目录之外。需要的逻辑是:

何时应该打开子菜单:

  1. 触摸设备中,当用户点击链接
  2. 指针中决定用户何时将鼠标悬停在链接上
  3. 打开菜单时,链接和子菜单必须获得“活动”类。

何时关闭子菜单:

  1. 单击“关闭”按钮时(位于子菜单内)
  2. 当另一个菜单打开时,第一个菜单应该关闭
  3. 触摸设备中,当您点击子菜单外的任意位置时
  4. 指针设备中,当鼠标离开子菜单区域时

已编辑:这是 100% 工作的最终代码 在@SilverSurfer awnser 和一些调整之后


$(".sub-menu").hide()

$("a.close-bt").click(function(){
    $(this).closest(".sub-menu").hide()
    $(this).closest(".sub-menu").removeClass("active")
    $(this).closest(document).find("a.menu-item").removeClass("active")
});

$(document).on('click mouseover', "ul.menu > a", function () {
    $("ul.menu > a").removeClass("active")
    $(".sub-menu").hide()
    var target = "."+$(this).attr("id")
    $(target).addClass("active")
    $(this).addClass("active")
    $(target).show()
});
$(".sub-menu").mouseleave(function() {
    $(this).hide()
    $(this).removeClass("active")
    $(this).closest(document).find("a.menu-item").removeClass("active")
});
// FUNCTIONAL STYLES

.menu {
	z-index: 2;
}
.menu a {
}
.sub-menu {
	//visibility: hidden;
	//visibility: show;
}
.close-bt {
	
}


// VISUAL STYLES, PLZ IGNORE
.menu {
}
.menu a {
	margin-right: 30px;
	background: green;
	display: inline-block;
	padding: 20px;
	color: white;
}
.menu a.active {
	background: red;
}
.sub-menu {
	width: 100px;
	height: 100px;
	background: lightblue;
	border: 2px solid black;
	z-index: 1;
	position: relative;
}
.sub-menu.active {
	visibility: show;
	background: blue;
}
.close-bt {
	background: red;
	color: white;
	padding: 10px;
	position: absolute;
	right: 10px;
	bottom: 10px;
}
ul { margin: 0; left: 0; padding: 0; }


.container  { position: absolute; top: 50px; left: 0; } 
.item1 { position: absolute; top: 10px; left: 0; }
.item2 { position: absolute; top: 10px; left: 110px; }
.item3 { position: absolute; top: 10px; left: 220px; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<ul class="menu">
	<a class="menu-item" id="item1" href="javascript:void(0);">Link 1</a>
	<a class="menu-item" id="item2" href="javascript:void(0);">Link 2</a>
	<a class="menu-item" id="item3" href="javascript:void(0);">Link 3</a>
</ul>


<div class="container">
	<div class="sub-menu item1">
    <a class="close-bt" href="javascript:void(0);">Close</a>
		Sub-menu 1
	</div>
	<div class="sub-menu item2">
    <a class="close-bt" href="javascript:void(0);">Close</a>
		Sub-menu 2
	</div>
	<div class="sub-menu item3">
    <a class="close-bt" href="javascript:void(0);">Close</a>
		Sub-menu 2
	</div>
</div>

【问题讨论】:

  • 请检查我的答案

标签: jquery hide show submenu


【解决方案1】:

这就是你要找的东西吗?

$(".sub-menu").hide()

$("a.close-bt").click(function(){
    $(this).closest(".sub-menu").hide()
    $(this).closest(".sub-menu").removeClass("active")
    $(this).closest(document).find("ul").removeClass("active")
});

$(document).on('click mouseover', "ul > a", function () {
    $(".sub-menu").hide()
    var target = "."+$(this).attr("id")
    $(target).addClass("active")
    $(this).closest("ul.menu").addClass("active")
    $(target).show()
});
// FUNCTIONAL STYLES

.menu {
	z-index: 2;
}
.menu a {
}
.sub-menu {
	//visibility: hidden;
	//visibility: show;
}
.close-bt {
	
}


// VISUAL STYLES, PLZ IGNORE
.menu {
}
.menu a {
	margin-right: 30px;
	background: green;
	display: inline-block;
	padding: 20px;
	color: white;
}
.menu a.active {
	background: red;
}
.sub-menu {
	width: 100px;
	height: 100px;
	background: lightblue;
	border: 2px solid black;
	z-index: 1;
	position: relative;
}
.sub-menu.active {
	visibility: show;
	background: blue;
}
.close-bt {
	background: red;
	color: white;
	padding: 10px;
	position: absolute;
	right: 10px;
	bottom: 10px;
}
ul { margin: 0; left: 0; padding: 0; }


.container  { position: absolute; top: 50px; left: 0; } 
.item1 { position: absolute; top: 10px; left: 0; }
.item2 { position: absolute; top: 10px; left: 110px; }
.item3 { position: absolute; top: 10px; left: 220px; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<ul class="menu">
	<a id="item1" href="javascript:void(0);">Link 1</a>
	<a id="item2" href="javascript:void(0);">Link 2</a>
	<a id="item3" href="javascript:void(0);">Link 3</a>
</ul>


<div class="container">
	<div class="sub-menu item1">
    <a class="close-bt" href="javascript:void(0);">Close</a>
		Sub-menu 1
	</div>
	<div class="sub-menu item2">
    <a class="close-bt" href="javascript:void(0);">Close</a>
		Sub-menu 2
	</div>
	<div class="sub-menu item3">
    <a class="close-bt" href="javascript:void(0);">Close</a>
		Sub-menu 2
	</div>
</div>

【讨论】:

  • 哇!漂亮的代码:) 它只缺少一件事:在指针设备中,鼠标离开子菜单时隐藏菜单......
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