perl数组搜索mysql结果

Question

我有一个包含手机号码的数据库。如何编写将所有数字放入数组并检查新数字是否已存在于该数组中的 perl 脚本？

创建表：

CREATE TABLE consumeruser (
  ConsumerId    int(10) NOT NULL AUTO_INCREMENT,
  ConsumerName  varchar(45) DEFAULT NULL,
  ConsumerMobNo varchar(10) DEFAULT NULL,
  PRIMARY KEY (ConsumerId)
) ENGINE=InnoDB AUTO_INCREMENT=4494 DEFAULT CHARSET=latin1

脚本：

#!/usr/bin/perl -w
use strict;
use warnings qw(all);

use DBI;
use Getopt::Long;
use Pod::Usage;
use Text::CSV_XS;

my $username = 'root';         # set your MySQL username
my $password = 'xxxx';         # set your MySQL password
my $database = 'app';          # set your MySQL database name
my $server   = 'localhost';    # set your server hostname (probably localhost)

my $dbh = DBI->connect( "DBI:mysql:$database;host=$server", $username, $password )
    || die "Could not connect to database: $DBI::errstr";

my $CustomerMobileNumber = 9999999;
my @MobileNumbers;
my $mobileNumberQuery = "select ConsumerMobNo from consumeruser";
my $sth               = $dbh->prepare($mobileNumberQuery);
$sth->execute();
while ( my @row = $sth->fetchrow_array() ) {
    push @MobileNumbers, $row;

    if (/test for is present/) {
        #9999999 found in array;
    } else {
        #9999999 not found in array;
    }
}

Answer 1

您可以要求数据库搜索号码：

my $mobileNumberQuery = "SELECT 1 FROM consumeruser WHERE ConsumerMobNo = ?";
my $sth = $dbh->prepare($mobileNumberQuery);
$sth->execute(9999999);
if ($sth->fetchrow_array) {
    print "Found.\n"
} else {
    print "Not found.\n";
}