【发布时间】:2017-09-21 06:20:10
【问题描述】:
背景: 我正忙于分析各种实验工作的数据。目的是导入带有各种工作表的 excel 文件。然后从数据中“过滤”噪声并找到所有样本的平均值。然后绘制图表并保存图表。
进展与问题: 我已经能够完成上述所有步骤,但是,各种样本与其平均值的最终图表对我来说似乎是错误的。我不确定“df.mean”是否是找到平均值的正确方法。我附上了我得到的图表,不知何故我不能同意平均值可以这么低? It can be seen that the saved image from my code cuts off the legend, how can I change this?
需要改进: 这是我关于 stackoverflow 的第一个问题,我对 Python 还是很陌生。代码看起来很“蓬松”,如果有任何关于缩短代码的建议,我将不胜感激。
我的密码:
#IMPORT LIBRARIES
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
#IMPORT DATA
excel_df= pd.ExcelFile('data.xlsx',delimiter = ';') #import entire excel file
sheet1=pd.read_excel('data.xlsx',sheetname=0,names=['time','void1','pressure1'])
sheet2=pd.read_excel('data.xlsx',sheetname=1,names=['time','void2','pressure2'])
sheet3=pd.read_excel('data.xlsx',sheetname=2,names=['time','void3','pressure3'])
sheet4=pd.read_excel('data.xlsx',sheetname=3,names=['time','void4','pressure4'])
sheet5=pd.read_excel('data.xlsx',sheetname=4,names=['time','void5','pressure5'])
sheet6=pd.read_excel('data.xlsx',sheetname=5,names=['time','void6','pressure6'])
sheet7=pd.read_excel('data.xlsx',sheetname=6,names=['time','void7','pressure7'])
sheet8=pd.read_excel('data.xlsx',sheetname=7,names=['time','void8','pressure8'])
sheet10=pd.read_excel('data.xlsx',sheetname=9,names=['time','void10','pressure10'])
#SORT VALUES TO FIND THE UNWANTED DATA
sheet1.sort_values('pressure1',ascending=False).head() #the pressure has noise so sort accordingly
#GET ONLY WANTED DATA WITHOUT NOISE
sheet1_new = sheet1[sheet1.pressure1 <=8] #exclude the noise above 8 bar
sheet2_new = sheet2[sheet2.pressure2 <=8] #exclude the noise above 8 bar
sheet3_new= sheet3[sheet3.pressure3 <=8] #exclude the noise above 8 bar
sheet4_new = sheet4[sheet4.pressure4 <=8] #exclude the noise above 8 bar
sheet5_new = sheet5[sheet5.pressure5 <=8] #exclude the noise above 8 bar
sheet6_new = sheet6[sheet6.pressure6 <=8] #exclude the noise above 8 bar
sheet7_new = sheet7[sheet7.pressure7 <=8] #exclude the noise above 8 bar
sheet8_new = sheet8[sheet8.pressure8 <=8] #exclude the noise above 8 bar
sheet10_new = sheet10[sheet10.pressure10 <=8] #exclude the noise above 8 bar
#MERGE THE DATASETS TO FIND AVERAGE OF ALL SAMPLES
#'MERGE' ONLY MERGES 2 DATAFRAMES AT A TIME
merge12_df = pd.merge(sheet1_new,sheet2_new, on='time')
merge34_df = pd.merge(sheet3_new,sheet4_new, on='time')
merge56_df = pd.merge(sheet5_new,sheet6_new, on='time')
merge78_df = pd.merge(sheet7_new,sheet8_new, on='time')
#MERGE ON FIRST OUTPUT
all_merged = merge12_df.merge(merge34_df, on='time').merge(merge56_df, on = 'time').merge(merge78_df, on = 'time').merge(sheet10_new, on = 'time')
#print(all_merged.head()) #check that all data is merged into one dataframe
#AVERAGE ALL PRESSURES
mean_all_pressures = all_merged[["pressure1", "pressure2","pressure3", "pressure4","pressure5", "pressure6","pressure7", "pressure8", "pressure10"]].mean(axis=1)
#PRINT AVERAGE VS ALL THE SAMPLES GRAPH
plt.figure(1)
plt.plot(all_merged.time,mean_all_pressures,'r.') #plot the average of all samples.
plt.plot(sheet1_new.time,sheet1_new.pressure1)
plt.plot(sheet2_new.time,sheet2_new.pressure2)
plt.plot(sheet3_new.time,sheet3_new.pressure3)
plt.plot(sheet4_new.time,sheet4_new.pressure4)
plt.plot(sheet5_new.time,sheet5_new.pressure5)
plt.plot(sheet6_new.time,sheet6_new.pressure6)
plt.plot(sheet7_new.time,sheet7_new.pressure7)
plt.plot(sheet8_new.time,sheet8_new.pressure8)
plt.plot(sheet10_new.time,sheet10_new.pressure10)
plt.legend(['Average','Sample 1','Sample 2','Sample 3','Sample 4','Sample 5','Sample 6','Sample 7','Sample 8','Sample 10'],bbox_to_anchor=(1.05, 1), loc=2, borderaxespad=0.)
plt.xlabel('Time (s)'),plt.ylabel('Pressure (bar)') #Specify the plot details
plt.savefig('AllPressures_vs_Average.png') #Save the plot for later use
plt.show() #Display the plot
【问题讨论】:
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for num in range(1,11):可以在这里节省很多代码... -
平均值是图表上的红点。我的第一张图片没有正确上传。
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通过自己明确地进行计算来检查平均值,即对过滤后的压力值求和并除以样本数。
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是什么让您认为均值是错误的?乍一看还不错。您是否尝试过打印出值并进行检查?
标签: python pandas dataframe python-import mean