丢弃匹配行并保留不匹配行 T-SQL答案

【问题标题】：Discard Matching Rows and Keep Unmatched Rows T-SQL丢弃匹配行并保留不匹配行 T-SQL
【发布时间】：2019-10-03 05:31:23
【问题描述】：

我有一个数据集并试图提出一个 SQL 查询来保留不匹配的行并丢弃匹配的行。

X_ID    Y_ID    Client_Id   User_Id date    
-------------------------------------------------------------
NULL    3000547 10000593    2001284 2019-03-11 10:59:21.214 X_ID <> Y_ID for Same Client_ID & User_ID so I want to keep these records.
NULL    3000547 10000593    2001284 2019-03-11 10:45:09.022 
NULL    3000547 10000593    2001284 2019-03-11 19:29:30.028 
NULL    3000547 10000593    2001284 2019-03-11 19:29:45.168 
NULL    3000547 10000593    2001284 2019-03-11 11:06:12.072 
NULL    NULL    10000622    2000576 2019-03-27 09:33:42.995 
NULL    NULL    10000622    2000576 2019-03-27 09:34:04.495 
NULL    NULL    10000622    2000576 2019-03-27 15:53:48.794 
NULL    NULL    10000622    2018815 2019-03-27 10:37:01.250 
4000954 4000954 10157846    2017957 2019-03-11 13:44:54.469 X_ID = Y_ID for Same Client_ID & User_ID so I want to discard these records.
4000954 4000954 10157846    2017957 2019-03-11 13:30:35.101 
4000954 4000954 10157846    2017957 2019-03-11 13:33:23.738 
4000954 4000954 10157846    2017957 2019-03-14 16:25:24.684 
4000954 4000954 10157846    2017957 2019-03-14 16:25:24.684 
4000954 4000954 10157846    2017957 2019-03-14 16:25:24.684 
4000954 4000954 10157846    2017957 2019-03-14 08:52:32.047 
4000954 4000954 10157846    2017957 2019-03-27 15:02:30.867 
4000954 4000954 10462731    2017957 2019-03-27 15:57:12.415 
4000954 NULL    10761202    2017957 2019-03-29 12:36:16.546 X_ID <> Y_ID for Same Client_ID & User_ID so I want to keep these records.
NULL    4000954 10792367    2000876 2019-03-25 16:22:33.457 
NULL    4000954 10792367    2001469 2019-03-29 13:54:25.354 
4000954 NULL    12312028    2017957 2019-03-29 12:35:47.140 
4000954 4000761 12642798    2017957 2019-03-25 16:18:19.522 There is one match of X_ID = Y_ID for same Clieny_ID & User_ID so I want to discard all three rows. 
4000954 4000954 12642798    2017957 2019-03-25 16:18:19.522 
4000954 4000954 12642798    2017957 2019-03-25 16:18:19.522 
4000954 4000761 12642798    2017957 2019-03-25 16:18:19.522 All the rows X_ID <> Y_ID for Same Client_id & User_ID so I want to keep these records
4000954 4000762 12642798    2017957 2019-03-25 16:18:19.522 
4000954 4000763 12642798    2017957 2019-03-25 16:18:19.522

【问题讨论】：

标签： sql-server tsql rows matching

【解决方案1】：

;WITH CTE AS 
(
    SELECT Distinct Client_ID, User_ID
    FROM [Your_Table]
    WHERE X_ID = Y_ID
)

SELECT *
FROM [Your_Table] AS T
LEFT OUTER JOIN CTE AS C
    ON T.Client_ID = C.Client_ID
    AND T.User_ID = C.User_ID
WHERE C.Client_ID IS NULL
AND C.User_ID IS NULL

【讨论】：

CTE 将选择所有匹配 X_ID 和 Y_ID 的 Client_ID 和 User_ID（即使单个记录匹配）。在查询中，我只是选择不是来自 CTE 的记录。在某种程度上，过滤掉具有匹配 X_ID 和 Y_ID 的 client_ID 和 User_ID。我希望我没有遗漏任何内容，并且查询会有所帮助。
谢谢你，它成功了，非常感谢你的帮助。我将继续努力以确保涵盖所有案例。
@Ally 如果答案对您有用，那么请将其标记为已接受。检查tour page。谢谢

【解决方案2】：

试试这个

SELECT DISTINCT X_ID, Y_ID, Client_Id, User_Id
FROM your_table

【讨论】：