【发布时间】：2014-04-24 02:21:54
【问题描述】：
假设我们有以下图片，代表功率谱图片
我的目标是：
1.检测该功率谱图的峰值
2.检测它的频率
首先，我从以下命令得到这张图片
[Pxx,f]=periodogram(B,[],[],100);
plot(f,Pxx);
其中 B 是输入信号，100 是采样频率，我尝试在 matlab 中使用 findpeaks 命令，像这样
[pxx_peaks,location]=findpeaks(Pxx);
然后找到
f(location)
但它似乎不适合实际频率，所以请告诉我如何从给定的峰值中找到频率？非常感谢
示例如下：
峰值如下：
0.417543614272817
0.389922187581014
0.381603315802419
0.601652859233616
0.396925294300794
0.369200511917405
0.477076452316346
0.792431584110476
0.612598437936600
0.564751537228850
0.940538666131177
0.600215481734847
0.985881201195063
0.950077461673118
1.24336273213410
1.84522775800633
1.73186592736729
3.46075557122590
4.93259798197976
8.47095716918618
25.2287636895831
1422.19492782494
60.8238733887811
11.3141744831953
8.65598040591953
3.92785491164888
2.51086405960291
2.27469230188760
1.90435488292485
1.25933693517960
1.52851575480462
0.933543409438383
1.21157308704582
0.821400666720535
1.28706199713640
1.19575886464231
0.736744959694641
0.986899895695809
0.758792061180657
0.542782326712391
0.704787750202814
0.998785634315287
0.522384453408780
0.602294251721841
0.525224294805813
0.624034405807298
0.498659616687732
0.656212420735658
0.866037361133916
0.624405636807668
0.435350646037440
1.22960953802959
0.891793067878849
1.06358076764171
1.34921178081181
1.02878577330537
1.93594290806582
1.14486512201656
2.01004088022982
2.24124811810385
2.15636037453584
4.81721425534142
4.87939454466131
10.5783535493504
27.0572221453758
1490.03057130613
62.3527480644562
13.6074209231800
9.85304975304259
16.3163128995995
74.1532966917877
1510.37374385290
27.7825124315786
8.66382951478539
7.72195587189507
6.06702456628919
3.35353608882459
4.90341095941571
5.07665716731356
4.47635486149688
9.79494608790444
22.9153086380666
1119.97978883924
57.0699524267842
15.2791339483160
5.36617545130941
3.90480316969632
2.58828964019220
1.16385064506181
1.55998411282069
1.14803074836796
0.468260146832541
0.467641715366303
0.698088976126660
0.504713663418641
0.375910057283262
0.331115262928959
0.204555648718379
0.182936666944843
0.293075999812128
0.272993318570981
0.280495615619829
0.148399626645134
位置：
3
6
8
11
13
16
18
20
22
25
27
30
32
34
37
39
42
44
46
49
51
55
58
61
63
65
68
70
73
75
77
79
82
85
87
89
91
94
96
99
101
103
106
108
111
113
115
118
120
123
125
127
129
132
134
137
139
141
144
146
148
151
153
156
158
162
165
167
171
174
176
179
183
185
188
190
193
195
197
199
202
204
208
211
213
216
218
220
222
225
227
230
232
234
237
239
241
243
245
248
250
252
254
和 f(位置)
f(location)
ans =
0.3906
0.9766
1.3672
1.9531
2.3438
2.9297
3.3203
3.7109
4.1016
4.6875
5.0781
5.6641
6.0547
6.4453
7.0313
7.4219
8.0078
8.3984
8.7891
9.3750
9.7656
10.5469
11.1328
11.7188
12.1094
12.5000
13.0859
13.4766
14.0625
14.4531
14.8438
15.2344
15.8203
16.4063
16.7969
17.1875
17.5781
18.1641
18.5547
19.1406
19.5313
19.9219
20.5078
20.8984
21.4844
21.8750
22.2656
22.8516
23.2422
23.8281
24.2188
24.6094
25.0000
25.5859
25.9766
26.5625
26.9531
27.3438
27.9297
28.3203
28.7109
29.2969
29.6875
30.2734
30.6641
31.4453
32.0313
32.4219
33.2031
33.7891
34.1797
34.7656
35.5469
35.9375
36.5234
36.9141
37.5000
37.8906
38.2813
38.6719
39.2578
39.6484
40.4297
41.0156
41.4063
41.9922
42.3828
42.7734
43.1641
43.7500
44.1406
44.7266
45.1172
45.5078
46.0938
46.4844
46.8750
47.2656
47.6563
48.2422
48.6328
49.0234
49.4141
【问题讨论】：
-
它怎么'不适合'？你能举一个你提供的图片的例子吗？
-
我已经更新了，请看
-
我想检测对应最大峰值的频率
标签： matlab signals signal-processing