我是 Django 的初学者，在 urls.py 中遇到语法错误

Question

这是我的个人/urls.py。我已经尝试解决这个问题好几天了。我知道这一定是一个非常愚蠢的错误，但我们将不胜感激。

from django.conf.urls import url, include
from . import views
urlpatterns = [
   url(r'^$',views.index, name='index'),
   url(r'contact/',views.contact, name='contact')
   url(r'about/',views.about, name='about')
]

这里是views.py

def index(request):
  return render(request, 'personal/home.html')

def contact(request):
  return render(request, 'personal/basic.html', {'content':['https://www.facebook.com/arjunkashyap30']})

def about(request):
  return render(request, 'personal/about.html', {'content': ["This is an abut 
page"]})

Answer 1

您在定义的每个端点的末尾忘记了comma。

urlpatterns = [
    url(r'^$',views.index, name='index'),
    url(r'contact/',views.contact, name='contact'),
    url(r'about/',views.about, name='about'),
]