【发布时间】:2019-05-02 06:33:48
【问题描述】:
如何在@register.filter(name='thumbnail') 模板标签中发送参数。我正在使用图像调整大小函数包含 2 个 args 图像对象和大小现在我想传递第三个参数 folder_name 但我无法找到它给出错误的解决方案 Could not parse the rest: 下面是函数是模板标签文件和模板。
模板标签功能
@register.filter(name='thumbnail')
def thumbnail(file, size='200x200',folder_name='users_images'):
x, y = [int(x) for x in size.split('x')]
# defining the filename and the miniature filename
filehead, filetail = os.path.split(file.path)
basename, format = os.path.splitext(filetail)
miniature = basename + '_' + size + format
#filename = file.path
#print(filehead+'/users_images/'+filetail)
if os.path.exists(filehead+'/'+folder_name+'/'+filetail):
filename = filehead+'/'+folder_name+'/'+filetail
filehead = filehead+'/'+folder_name+'/'
else:
filename = file.path
#print(filename)
miniature_filename = os.path.join(filehead, miniature)
filehead, filetail = os.path.split(file.url)
miniature_url = filehead + '/' + miniature
if os.path.exists(
miniature_filename
) and os.path.getmtime(filename) > os.path.getmtime(
miniature_filename
):
os.unlink(miniature_filename)
# if the image wasn't already resized, resize it
if not os.path.exists(miniature_filename):
image = Image.open(filename)
new_image = image.resize([x, y], Image.ANTIALIAS)
# image.thumbnail([x, y], Image.ANTIALIAS)
try:
# image.save(miniature_filename, image.format, quality=90, optimize=1)
new_image.save(miniature_filename, image.format,
quality=95, optimize=1)
except:
return miniature_url
return miniature_url
模板文件 我尝试了 2 种不同的类型
{{ contact_list.picture|thumbnail:'200x200' 'contacts'}}
{{ contact_list.picture|thumbnail:'200x200','contacts'}}
如果有人有解决方案,请帮助我。 谢谢
【问题讨论】:
标签: django django-templates django-template-filters