【问题标题】:cudaMalloc error when I try to copy array of pointers to device当我尝试将指针数组复制到设备时出现 cudaMalloc 错误
【发布时间】:2014-02-03 21:18:58
【问题描述】:

我有一个简单的基于粒子的刚体动力学代码,每个刚体由许多具有质量、位置、速度等的小粒子组成...现在我想将此 cpu 代码移植到 gpu。

对于结构,我选择使用指针数组int** d_rigid_particle_indices,它的每个元素都指向其子粒子索引的数组(因为我使用基数排序来对每一帧粒子进行排序,所以索引每帧都会改变。所以我将使用双缓冲方案 -> int** d_rigid_particle_indices[2];)

这是从主机复制数据到设备的数据结构和函数:

typedef struct{
// Particle based rigid body dynamics
float4*       d_rb_pos;                     
float4*       d_rb_vel;
float4*       d_rb_angular_velocity;
float4*       d_rb_linear_momentum;
float4*       d_rb_angular_momentum;
float4*       d_rb_force;
float4*       d_rb_torque;
float4*       d_rb_quaternion;
float*        d_rb_rotation_matrix;         
float*        d_rb_inv_inertia_local;       
float*        d_rb_inv_inertia_world;   
float*        d_rb_mass;
int**         d_rigid_particle_indices[2];

}d_RigidBody;

void CopyRigidBodyDataHostToDevice(d_RigidBody& d_rb,std::vector<RigidBody*>& rigidbodies_h){
const int num_rigid_bodies = rigidbodies_h.size();

// allocate host mem for top level pointer array
int** h_rigid_bodies = (int**)malloc(num_rigid_bodies*sizeof(int*));
for (int i = 0; i < num_rigid_bodies; ++i)
    h_rigid_bodies[i] = NULL;

// allocate host&device mem for child particle index array
for (int i = 0; i < num_rigid_bodies; ++i)
{
    RigidBody* rb = rigidbodies_h[i];
    if (rb)
    {
        std::vector<int>& rp_indices = rb->getRigidBodyParticleIndicesArray();
        const int num_particles = rp_indices.size();
        int* temp_rp_indices = (int*)malloc(num_particles*sizeof(int));
        for (int j = 0; j < num_particles; ++j)
        {
            temp_rp_indices[j] = rp_indices[j];
        }           
        int * temp_ptr;
        CUDA_SAFE_CALL( cudaMalloc( ( (void**)&temp_ptr, num_particles*sizeof(int) ) ) );       // allocate device mem for child pointer
        h_rigid_bodies[i] = temp_ptr;
        temp_ptr = NULL;
        for (int k = 0; k < num_particles; ++k)
        {
            // copy RigidParticleIndices per rigid body from host to device
            CUDA_SAFE_CALL( cudaMemcpy(h_rigid_bodies[i], temp_rp_indices, num_particles*sizeof(int), cudaMemcpyHostToDevice) );    //h_rigid_bodies[i] stores the device mem pointer
        }
        if (temp_rp_indices)
            free(temp_rp_indices);              
    }
}

// allocate device mem for top level pointer array
CUDA_SAFE_CALL( cudaMalloc( (void**)&(d_rb.d_rigid_particle_indices[0]), num_rigid_bodies*sizeof(int*) ) ); // pointer array
CUDA_SAFE_CALL( cudaMalloc( (void**)&(d_rb.d_rigid_particle_indices[1]), num_rigid_bodies*sizeof(int*) ) ); // pointer array

// now we're ready to copy top level pointer array from host to device 
CUDA_SAFE_CALL( cudaMemcpy(d_rb.d_rigid_particle_indices[0], h_rigid_bodies, num_rigid_bodies*sizeof(int*), cudaMemcpyHostToDevice) );

// clean up
if (h_rigid_bodies)
{
    for (int i = 0; i < num_rigid_bodies; ++i)
    {
        if (h_rigid_bodies[i])
        {
            free(h_rigid_bodies[i]);
        }
    }
    free(h_rigid_bodies);
}   

}

编译后,这行代码出现错误“没有重载函数“cudaMalloc”的实例与参数列表参数类型匹配:(unsigned int)”:

CUDA_SAFE_CALL( cudaMalloc( ( (void**)&temp_ptr, num_particles*sizeof(int) ) ) );       // allocate device mem for child pointer.

有什么建议吗?

谢谢。

【问题讨论】:

    标签: c cuda


    【解决方案1】:

    您使用了过多的一对括号。所以编译器只看到一个参数被传递给cudaMalloc 调用。将行改为

    CUDA_SAFE_CALL( cudaMalloc( (void**)&temp_ptr, num_particles*sizeof(int) ) );
    

    它有效。

    【讨论】:

    • 谢谢。现在它起作用了。我想给你的答案加一分,但我只有 14 分。^-^
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