【发布时间】:2018-01-20 19:21:53
【问题描述】:
运行这个版本的内核 4.11.8-1.el6.elrepo.x86_64 并想知道为什么 TCP 堆栈会发送一些 RST 数据包,即是否存在与 BSD net.inet.tcp.log_debug=1 对应的 Linux 版本?
以下是需要原因的情况之一。在握手的最终到达 ACK 之后立即发送 RST。可以看到SYN丢了好几次,最后一个ACK也超过1s没有到达。但仍不清楚为什么要发送 RST。禁用 syn cookie 没有帮助。
15:27:41.166799 IP CLIENT.16537 > SERVER.80: Flags [S], seq 1397492268, win 29200, options [mss 1440,sackOK,TS val 1230199 ecr 0,nop,wscale 6], length 0
15:27:41.166820 IP SERVER.80 > CLIENT.16537: Flags [S.], seq 1773519351, ack 1397492269, win 29200, options [mss 1460,nop,nop,sackOK,nop,wscale 9], length 0
15:27:42.069572 IP CLIENT.16537 > SERVER.80: Flags [S], seq 1397492268, win 29200, options [mss 1460,sackOK,TS val 1230299 ecr 0,nop,wscale 6], length 0
15:27:42.069590 IP SERVER.80 > CLIENT.16537: Flags [S.], seq 1773519351, ack 1397492269, win 29200, options [mss 1460,nop,nop,sackOK,nop,wscale 9], length 0
15:27:43.123141 IP SERVER.80 > CLIENT.16537: Flags [S.], seq 1773519351, ack 1397492269, win 29200, options [mss 1460,nop,nop,sackOK,nop,wscale 9], length 0
15:27:44.067228 IP CLIENT.16537 > SERVER.80: Flags [S], seq 1397492268, win 29200, options [mss 1460,sackOK,TS val 1230499 ecr 0,nop,wscale
6], length 0
15:27:44.067240 IP SERVER.80 > CLIENT.16537: Flags [S.], seq 1773519351, ack 1397492269, win 29200, options [mss 1460,nop,nop,sackOK,nop,wscale 9], length 0
15:27:46.547072 IP CLIENT.16537 > SERVER.80: Flags [.], ack 1, win 457, length 0
15:27:46.547094 IP SERVER.80 > CLIENT.16537: Flags [R], seq 1773519352, win 0, length 0
15:27:46.548177 IP CLIENT.16537 > SERVER.80: Flags [.], ack 1, win 457, options [nop,nop,sack 1 {0:1}], length 0
15:27:46.548186 IP SERVER.80 > ClIENT.16537: Flags [R], seq 1773519352, win 0, length 0
感谢您的帮助。
【问题讨论】:
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不是问题的答案,但在这种特定情况下,由于客户端在“15:27:46.547072”不正确的“ack 1”发送了 RST(应该是“确认 1773519352")
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谢谢,但是握手后的ack数1只是tcpdump调整的,方便阅读。
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你可以用
iptables -I OUTPUT -p tcp -m tcp --tcp-flags SYN,ACK,FIN,RST RST -j LOG追踪他们,然后查看/var/log/kern.log
标签: linux tcp linux-kernel tcpdump