我认为您不能创建局部变量是否正确？

Question

只是想知道我不断收到下面的错误，但脚本的其余部分有效。

CREATE VIEW View_I_Want AS 

DECLARE @MinDate AS DATE

SET @MinDate = 
    (SELECT MIN(Full_Date) AS First_Date
    FROM tbl.Calendar
    WHERE [Fin_Year] = 
        (SELECT [Fin_Year] - 1
        FROM tbl.Calendar
        WHERE Full_Date = CAST(GETDATE() AS DATE)))


SELECT DISTINCT MIN(CAST(Data_Table_Date_Column AS DATE)) AS Min_Date,
    MAX(CAST(Data_Table_Date_Column AS DATE)) AS Max_Date



FROM data_Table
WHERE CAST(Data_Table_Date_Column AS DATE) >= @MinDate

消息 156，级别 15，状态 1，过程如何，第 3 行语法不正确 靠近关键字“DECLARE”。

Answer 1

您不能在视图定义中声明 variables。但另一种方法是：

CREATE VIEW View_I_Want
AS
     SELECT DISTINCT
            MIN(CAST(Data_Table_Date_Column AS DATE)) AS Min_Date,
            MAX(CAST(Data_Table_Date_Column AS DATE)) AS Max_Date
     FROM data_Table
     WHERE CAST(Data_Table_Date_Column AS DATE) >=
     (
         SELECT MIN(Full_Date) AS First_Date
         FROM tbl.Calendar
         WHERE [Fin_Year] =
         (
             SELECT [Fin_Year] - 1
             FROM tbl.Calendar
             WHERE Full_Date = CAST(GETDATE() AS DATE)
         )
     );

Answer 2

您希望该变量作为存储过程的参数吗？在这种情况下，您不使用“Declare”，但如果您希望它作为过程中的变量，请指定数据类型，请使用 Declare @variableName AS 数据类型

CREATE PROCEDURE dbo.YourStoredProcedure (
@parameter INT )
AS
BEGIN
DECLARE @variable1 AS INT
DECLARE @variable2 AS INT

....

END