在包含 [重复] 的情况下，视图必须是可调用的或列表元组

Question

Django==1.10.5 登录。 我已经制作了登录表单，然后编写了这些代码并想运行服务器

Urls.py:

    urlpatterns = [
        #previous login view
        #url(r'^login/$', views.user_login, name='login'),
        #login/logout urls
        url(r'^$', views.dashboard, name='dashboard'),

        url(r'^login/$', 'login', name='login'),
        url(r'^logout/$', 'django.contrib.auth.views.logout', name='logout'),
        url(r'^logout-thenlogin/$','django.contrib.auth.views.logout_then_login', 
            name='logout_then_login'),

]

Views.py:
from django.shortcuts import render, redirect
from django.http import HttpResponse
from django.contrib.auth import authenticate, login
from django.contrib.auth.decorators import login_required
from .forms import LoginForm



def user_login(request):
    if request.method == 'POST':
        form = LoginForm(request.POST)
        if form.is_valid():
            cd = form.cleaned_data
            user = authenticate(username=cd['username'], password=cd['password'])
            if user is not None:
                if user.is_active:
                    login(request, user)
                    return HttpResponse('Authenticated successfully')
                else:
                    return HttpResponse('Disabled account')
            else:
                return HttpResponse('Invalid login')
    else:
        form = LoginForm()
    return render(request, 'account/login.html', {'form': form})

@login_required
def dashboard(request):
    return render(request, 'account/dashboard.html', {'section': 'dashboard'})

当我想运行服务器时，我收到了这条消息： 在包含的情况下，视图必须是可调用的或列表\元组

Answer 1

Django 1.10+ 不再允许您在 URL 模式中将视图指定为字符串（例如“myapp.views.home”）。

解决方案是更新您的 urls.py 以包含可调用的视图。这意味着您必须在 urls.py 中导入视图。如果您的 URL 模式没有名称，那么现在是添加名称的好时机，因为使用点分 Python 路径进行反转不再有效。

urlpatterns = [
        #previous login view
        #url(r'^login/$', views.user_login, name='login'),
        #login/logout urls
        url(r'^$', views.dashboard, name='dashboard'),

        url(r'^login/$', your_app_name.views.user_login, name='login'),
        url(r'^logout/$', django.contrib.auth.views.logout, name='logout'),
        url(r'^logout-thenlogin/$', django.contrib.auth.views.logout_then_login, 
            name='logout_then_login'),

]