【发布时间】:2019-06-28 06:57:40
【问题描述】:
尝试解析 JSON 文档,Spark 给我一个错误:
Exception in thread "main" org.apache.spark.sql.AnalysisException: Since Spark 2.3, the queries from raw JSON/CSV files are disallowed when the
referenced columns only include the internal corrupt record column
(named _corrupt_record by default). For example:
spark.read.schema(schema).json(file).filter($"_corrupt_record".isNotNull).count()
and spark.read.schema(schema).json(file).select("_corrupt_record").show().
Instead, you can cache or save the parsed results and then send the same query.
For example, val df = spark.read.schema(schema).json(file).cache() and then
df.filter($"_corrupt_record".isNotNull).count().;
at org.apache.spark.sql.execution.datasources.json.JsonFileFormat.buildReader(JsonFileFormat.scala:120)
...
at org.apache.spark.sql.execution.SQLExecution$.withNewExecutionId(SQLExecution.scala:73)
at org.apache.spark.sql.Dataset.withAction(Dataset.scala:3364)
at org.apache.spark.sql.Dataset.head(Dataset.scala:2545)
at org.apache.spark.sql.Dataset.take(Dataset.scala:2759)
at org.apache.spark.sql.Dataset.getRows(Dataset.scala:255)
at org.apache.spark.sql.Dataset.showString(Dataset.scala:292)
at org.apache.spark.sql.Dataset.show(Dataset.scala:746)
at org.apache.spark.sql.Dataset.show(Dataset.scala:705)
at xxx.MyClass.xxx(MyClass.java:25)
我已经尝试在几个在线编辑器中打开 JSON 文档并且它是有效的。
这是我的代码:
Dataset<Row> df = spark.read()
.format("json")
.load("file.json");
df.show(3); // this is line 25
我正在使用 Java 8 和 Spark 2.4。
【问题讨论】:
标签: java json apache-spark