【发布时间】:2018-03-21 07:06:30
【问题描述】:
具体来说,我正在尝试使用Applicative 扩展我的Functor 类型类。
trait Functor[F[_]] {
def fmap[A, B](r: F[A], f: A => B): F[B]
}
object Functor {
implicit class FunctorOps[A, F[_]: Functor](xs: F[A]) {
def fmap[B](f: A => B): F[B] = implicitly[Functor[F]].fmap(xs, f)
}
implicit def SeqFunctor: Functor[Seq] = new Functor[Seq] {
def fmap[A, B](r: Seq[A], f: A => B) = r map f
}
}
trait Applicative[F[_]] extends Functor[F] {
// What I want to do, but this *does not* work.
def fmap[A, B](r: F[A], f: A => B): F[B] = Functor.FunctorOps[A, F](r).fmap(f)
def pure[A](x: A): F[A]
def fapply[A, B](r: F[A], f: F[A => B]): F[B]
}
object Applicative {
implicit class ApplicativeOps[A, F[_]](a: F[A])(implicit F: Applicative[F]) {
def fapply[B](f: F[A => B]): F[B] = F.fapply(a, f)
}
implicit def SeqApplicative: Applicative[Seq] = new Applicative[Seq] {
def pure[A](x: A) = Seq(x)
def fapply[A, B](xs: Seq[A], fs: Seq[A => B]): Seq[B] = xs.flatMap(x => fs.map(_(x)))
}
}
它的要点是我必须为所有Applicatives 实现fmap,但它实际上应该与我的FunctorOps 类中定义的方法相同。我该如何以最简洁的方式做到这一点?
【问题讨论】:
标签: scala generics functional-programming typeclass implicit