如何在python中比较2个json [关闭]

Question

如何在python中比较2个json对象下面是示例json。

sample_json1={
    {
       "globalControlId": 72,
       "value": 0,
       "controlId": 2
   },
   {
       "globalControlId": 77,
       "value": 3,
       "controlId": 7
   }
}

sample_json2={
    {
       "globalControlId": 72,
       "value": 0,
       "controlId": 2
   },
   {
       "globalControlId": 77,
       "value": 3,
       "controlId": 7
   }
}

Answer 1

似乎通常的比较工作正常

import json
x = json.loads("""[
    {
       "globalControlId": 72,
       "value": 0,
       "controlId": 2
   },
   {
       "globalControlId": 77,
       "value": 3,
       "controlId": 7
   }
]""")

y = json.loads("""[{"value": 0, "globalControlId": 72,"controlId": 2}, {"globalControlId": 77, "value": 3, "controlId": 7 }]""")

x == y # result: True    

Answer 2

这些不是有效的 JSON / Python 对象，因为数组 / 列表字面量在 [] 而不是 {} 内：

UPDATE：比较字典列表（对象的序列化JSON数组），同时忽略列表项的顺序，列表需要排序或转换为集合 ：

sample_json1=[{"globalControlId": 72, "value": 0, "controlId": 2},
              {"globalControlId": 77, "value": 3, "controlId": 7}]
sample_json2=[{"globalControlId": 77, "value": 3, "controlId": 7},
              {"globalControlId": 77, "value": 3, "controlId": 7}, # duplicity
              {"globalControlId": 72, "value": 0, "controlId": 2}]

# dictionaries are unhashable, let's convert to strings for sorting
sorted_1 = sorted([repr(x) for x in sample_json1])
sorted_2 = sorted([repr(x) for x in sample_json2])
print(sorted_1 == sorted_2)

# in case the dictionaries are all unique or you don't care about duplicities,
# sets should be faster than sorting
set_1 = set(repr(x) for x in sample_json1)
set_2 = set(repr(x) for x in sample_json2)
print(set_1 == set_2)